Question

我有一个实际的函数，用字符串中的其他特定字符替换特定的字符。它工作正常，但我觉得这个功能很难看。如何通过更优雅的功能替换此功能？

private string CorrectString(string data)
{
    string retData = string.Empty;

    for (int j = 0; j < data.Length; j++)
    {
        char myChar = data[j];

        switch (myChar)
        {
            case 'à': 
                myChar = '@';
                break;
            case 'ç': 
                myChar = '\\';
                break;
            case '[': 
                myChar = '°';
                break;
            case '!': 
                myChar = '!';
                break;
            case 'é': 
                myChar = '{';
                break;
            case 'è': 
                myChar = '}';
                break;
            case ']': 
                myChar = '§';
                break;
            case '¦': 
                myChar = 'ù';
                break;
            case '`': 
                myChar = 'µ';
                break;
            case '#': 
                myChar = '£';
                break;
            case '@': 
                myChar = 'à';
                break;
            case '°': 
                myChar = '[';
                break;
            case '¤': 
                myChar = '€';
                break;
            case 'µ': 
                myChar = '`';
                break;
            case '~':
                myChar = '"';
                break;
            case 'Ý': 
                myChar = 'Ý';
                break;
            case '¢': 
                myChar = '¢';
                break;
            case '£': 
                myChar = '#';
                break;
            case '§': 
                myChar = ']';
                break;
            case '¬': 
                myChar = '¬';
                break;
            case '|': 
                myChar = '|';
                break;
            case '"':
                myChar = '~';
                break;
            case '{': 
                myChar = 'é';
                break;
            case '}': 
                myChar = 'è';
                break;
            case 'ù': 
                myChar = '¦';
                break;
            case '\\':
                myChar = 'ç';
                break;
        }

        retData = retData.Insert(j, myChar.ToString());
    }

    return retData;
}

Answer 1

解决方案1 

您只需将字符保存在两个字符串中即可：

var toTranslate = "àç[!é...";
var translateTo = @"@\°...";

然后在找到字符时进行翻译：

int index = toTranslate.IndexOf(myChar);
if (index > -1)
{
    myChar = translateTo[index];
}

解决方案2

另一种有效但不太可读的方法是存储Dictionary<char, char>并像这样使用它：

myDictionary['à'] = '@';
myDictionary['ç'] = '\\';
...
if (myDictionary.Keys.Contains(myChar))
{
    myChar = myDictionary[myChar];
}

Answer 2

如果不考虑速度，您可能需要创建Dictionary<char, char>并为字典的每个键检查它是否等于当前字符。如果是，则用适当的值替换它。推进一个角色并继续。

Answer 3

或一系列替换语句：

myCleanString= Regex.Replace(data, "à", @"@")
                        .Replace("ç", "\\")
                        .Replace("[", "°") ...

Answer 4

_MyString1 = "@\\°!"; // those you put in the partial class or public class of your program
_MyString1 = "@\\°!";          
string c = _MyString1.Substring(_MyString.IndexOf("à"),1);

用其他特定字符替换细节字符

4 个答案: