Question

我想使用django.core.paginator，我对render_to_response函数有疑问。 views.py中名为 pages 的变量应该返回页数等但不是。我看到的所有故事，但分页不起作用。 views.py 文件如下所示：

    from django.shortcuts import render_to_response, get_object_or_404
    from django.db.models import Q
    from cms.models import Story, Category
    from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger

    def listing(request):
        story_list = Story.objects.all()
        p = Paginator(story_list, 2) # Show 2 contacts per page
        page = request.GET.get('page')
        try:
            pages = p.page(page)
        except PageNotAnInteger:
            # If page is not an integer, deliver first page.
            pages = p.page(1)
        except EmptyPage:
            # If page is out of range (e.g. 9999), deliver last page of results.
            pages = p.page(p.num_pages)
        return render_to_response('/usr/local/lib/python2.7/dist-packages/django/bin/project_003/cms/templates/cms/story_list.html', {"pages": pages})

story_list.html 就像这样：

    {% extends "/usr/local/lib/python2.7/dist-packages/django/bin/project_003/cms/templates/cms/base.html" %}
    {% block content %}
        {% if heading %}
            <h1>{{ heading }}</h1>
        {% endif %}
        <ul id="story-list">
            {% for story in story_list %}
                <li><a href="{{story.get_absolute_url}}">{{story.title}}</a></li><br>
        {{pages.p.num_pages}}
    {% endfor %}

    <div class="pagination">
        <span class="step-links">
            {% if pages.has_previous %}
                <a href="?page={{ pages.previous_page_number }}">previous</a>
            {% endif %}

            <span class="current">
                Page {{ pages.number }} of {{ pages.paginator.num_pages }}.
            </span>

            {% if pages.has_next %}
                <a href="?page={{ pages.next_page_number }}">next</a>
            {% endif %}
        </span>
    </div>
</ul>

    {% endblock %}

哪里出错了？

Answer 1

直接从文档中更改变量名称：https://docs.djangoproject.com/en/dev/topics/pagination/#using-paginator-in-a-view

观点：

def listing(request):
    story_list = Story.objects.all()
    p = Paginator(story_list, 2) # Show 2 contacts per page
    page = request.GET.get('page')
    try:
        stories = p.page(page)
    except PageNotAnInteger:
        # If page is not an integer, deliver first page.
        stories = p.page(1)
    except EmptyPage:
        # If page is out of range (e.g. 9999), deliver last page of results.
        stories = p.page(p.num_pages)
    return render_to_response('/usr/local/lib/python2.7/dist-packages/django/bin/project_003/cms/templates/cms/story_list.html', {"stories": stories})

模板：

<ul id="story-list">
    {% for story in stories %}
        <li><a href="{{story.get_absolute_url}}">{{story.title}}</a></li><br>
    {% endfor %}
</ul>

<div class="pagination">
    <span class="step-links">
        {% if stories.has_previous %}
            <a href="?page={{ stories.previous_page_number }}">previous</a>
        {% endif %}

        <span class="current">
            Page {{ stories.number }} of {{ stories.paginator.num_pages }}.
        </span>

        {% if stories.has_next %}
            <a href="?page={{ stories.next_page_number }}">next</a>
        {% endif %}
    </span>
</div>

django paginator，页数不归

1 个答案: