假设我有一本字典:
x = {"x1":1,"x2":2,"x3":3}
我还有另一本字典:
y = {"y1":1,"y2":2,"y3":3}
有没有任何巧妙的方法来构建前两个字典中的第三个字典:
z = {"y1":1,"x2":2,"x1":1,"y2":2}
答案 0 :(得分:6)
如果你想要整个2个词组:
x = {"x1":1,"x2":2,"x3":3}
y = {"y1":1,"y2":2,"y3":3}
z = dict(x.items() + y.items())
print z
<强>输出:强>
{'y2': 2, 'y1': 1, 'x2': 2, 'x3': 3, 'y3': 3, 'x1': 1}
如果你想要部分字典:
x = {"x1":1,"x2":2,"x3":3}
y = {"y1":1,"y2":2,"y3":3}
keysList = ["x2", "x1", "y1", "y2"]
z = {}
for key, value in dict(x.items() + y.items()).iteritems():
if key in keysList:
z.update({key: value})
print z
<强>输出强>
{'y1': 1, 'x2': 2, 'x1': 1, 'y2': 2}
答案 1 :(得分:5)
您可以copy
使用x
,然后update
使用y
添加密钥和值:
z = x.copy()
z.update(y)
答案 2 :(得分:0)
尝试这样的事情:
dict([(key, d[key]) for d in [x,y] for key in d.keys() if key not in ['x3', 'y3']])
{'x2': 2, 'y1': 1, 'x1': 1, 'y2': 2}