我将一个大对象数组序列化为json http响应流。现在我想一次一个地从流中反序列化这些对象。是否有任何c#库可以让我这样做?我看过json.net,但似乎我必须立即反序列化完整的对象数组。
[{large json object},{large json object}.....]
澄清:我想一次从流中读取一个json对象并反序列化。
答案 0 :(得分:45)
为了逐步读取JSON,您需要将JsonTextReader
与StreamReader
结合使用。但是,您不一定要从阅读器手动读取所有JSON。您应该能够利用Linq-To-JSON API从阅读器加载每个大对象,以便您可以更轻松地使用它。
举个简单的例子,假设我有一个看起来像这样的JSON文件:
[
{
"name": "foo",
"id": 1
},
{
"name": "bar",
"id": 2
},
{
"name": "baz",
"id": 3
}
]
从文件中逐步读取它的代码可能类似于以下内容。 (在您的情况下,您将使用您的响应流替换FileStream。)
using (FileStream fs = new FileStream(@"C:\temp\data.json", FileMode.Open, FileAccess.Read))
using (StreamReader sr = new StreamReader(fs))
using (JsonTextReader reader = new JsonTextReader(sr))
{
while (reader.Read())
{
if (reader.TokenType == JsonToken.StartObject)
{
// Load each object from the stream and do something with it
JObject obj = JObject.Load(reader);
Console.WriteLine(obj["id"] + " - " + obj["name"]);
}
}
}
上述输出如下:
1 - foo
2 - bar
3 - baz
答案 1 :(得分:4)
我简化了解析器/解串器的一个示例/测试,以更直接地回答这个问题的用例。
以下是测试数据:
https://github.com/ysharplanguage/FastJsonParser/tree/master/JsonTest/TestData
(参见fathers.json.txt)
以下是示例代码:
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
// Our stuff
using System.Text.Json;
//...
public class FathersData
{
public Father[] fathers { get; set; }
}
public class Someone
{
public string name { get; set; }
}
public class Father : Someone
{
public int id { get; set; }
public bool married { get; set; }
// Lists...
public List<Son> sons { get; set; }
// ... or arrays for collections, that's fine:
public Daughter[] daughters { get; set; }
}
public class Child : Someone
{
public int age { get; set; }
}
public class Son : Child
{
}
public class Daughter : Child
{
public string maidenName { get; set; }
}
//...
static void FilteredFatherStreamTestSimplified()
{
// Get our parser:
var parser = new JsonParser();
// (Note this will be invoked thanks to the "filters" dictionary below)
Func<object, object> filteredFatherStreamCallback = obj =>
{
Father father = (obj as Father);
// Output only the individual fathers that the filters decided to keep (i.e., when obj.Type equals typeof(Father)),
// but don't output (even once) the resulting array (i.e., when obj.Type equals typeof(Father[])):
if (father != null)
{
Console.WriteLine("\t\tId : {0}\t\tName : {1}", father.id, father.name);
}
// Do not project the filtered data in any specific way otherwise,
// just return it deserialized as-is:
return obj;
};
// Prepare our filter, and thus:
// 1) we want only the last five (5) fathers (array index in the resulting "Father[]" >= 29,995),
// (assuming we somehow have prior knowledge that the total count is 30,000)
// and for each of them,
// 2) we're interested in deserializing them with only their "id" and "name" properties
var filters =
new Dictionary<Type, Func<Type, object, object, int, Func<object, object>>>
{
// We don't care about anything but these 2 properties:
{
typeof(Father), // Note the type
(type, obj, key, index) =>
((key as string) == "id" || (key as string) == "name") ?
filteredFatherStreamCallback :
JsonParser.Skip
},
// We want to pick only the last 5 fathers from the source:
{
typeof(Father[]), // Note the type
(type, obj, key, index) =>
(index >= 29995) ?
filteredFatherStreamCallback :
JsonParser.Skip
}
};
// Read, parse, and deserialize fathers.json.txt in a streamed fashion,
// and using the above filters, along with the callback we've set up:
using (var reader = new System.IO.StreamReader(FATHERS_TEST_FILE_PATH))
{
FathersData data = parser.Parse<FathersData>(reader, filters);
System.Diagnostics.Debug.Assert
(
(data != null) &&
(data.fathers != null) &&
(data.fathers.Length == 5)
);
foreach (var i in Enumerable.Range(29995, 5))
System.Diagnostics.Debug.Assert
(
(data.fathers[i - 29995].id == i) &&
!String.IsNullOrEmpty(data.fathers[i - 29995].name)
);
}
Console.ReadKey();
}
其余位可在此处获取:
https://github.com/ysharplanguage/FastJsonParser
“HTH,
答案 2 :(得分:0)
这是我的解决方案(从不同来源合并,但主要基于"Checking for Protocol Conformance"解决方案)将巨大的JSON文件(对象数组)转换为任何通用对象的XML文件。
JSON看起来像这样:
{
"Order": [
{ order object 1},
{ order object 2},
{...}
{ order object 10000},
]
}
输出XML:
<Order>...</Order>
<Order>...</Order>
<Order>...</Order>
C#代码:
XmlWriterSettings xws = new XmlWriterSettings { OmitXmlDeclaration = true };
using (StreamWriter sw = new StreamWriter(xmlFile))
using (FileStream fs = new FileStream(jsonFile, FileMode.Open, FileAccess.Read))
using (StreamReader sr = new StreamReader(fs))
using (JsonTextReader reader = new JsonTextReader(sr))
{
//sw.Write("<root>");
while (reader.Read())
{
if (reader.TokenType == JsonToken.StartArray)
{
while (reader.Read())
{
if (reader.TokenType == JsonToken.StartObject)
{
JObject obj = JObject.Load(reader);
XmlDocument doc = JsonConvert.DeserializeXmlNode(obj.ToString(), "Order");
sw.Write(doc.InnerXml); // a line of XML code <Order>...</Order>
sw.Write("\n");
//this approach produces not strictly valid XML document
//add root element at the beginning and at the end to make it valid XML
}
}
}
}
//sw.Write("</root>");
}
答案 3 :(得分:0)
使用Cinchoo ETL-一个开放源代码库,您可以有效地解析低内存占用的大型JSON。由于对象是在基于流的拉模型中构造并返回的,所以
using (var p = new ChoJSONReader(** YOUR JSON FILE **))
{
foreach (var rec in p)
{
Console.WriteLine($"Name: {rec.name}, Id: {rec.id}");
}
}
有关更多信息,请访问codeproject文章。
希望有帮助。