Question

我是春天新手，我正在尝试将openId集成到我的应用程序中

我不断收到此异常，因此发生404错误。

控制台日志：

org.springframework.beans.factory.parsing.BeanDefinitionParsingException: Configuration problem: spring-security-web classes are not available. You need these to use <filter-chain-map>

我的web.xml： -

<servlet>  
    <servlet-name>dispatcher</servlet-name>  
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  
    <load-on-startup>1</load-on-startup>  
</servlet>  

<servlet-mapping>  
    <servlet-name>dispatcher</servlet-name>  
    <url-pattern>/rest/*</url-pattern>  
</servlet-mapping> 

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        /WEB-INF/spring/applicationContext-security.xml
    </param-value>
</context-param>

<welcome-file-list>  
    <welcome-file>index.jsp</welcome-file>  
</welcome-file-list>

部分如果我的dispatcher-servlet.xml： -

   <?xml version="1.0" encoding="UTF-8"?>
    <beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:oxm="http://www.springframework.org/schema/oxm"
xsi:schemaLocation="
    http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/tx
    http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
    http://www.springframework.org/schema/oxm
    http://www.springframework.org/schema/oxm/spring-oxm-3.0.xsd">

<context:property-placeholder location="classpath:jdbc.properties" />
<context:component-scan base-package="com.kratin" />

<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
    <property name="order" value="1" />
    <property name="messageConverters">
        <list>
            <!-- Default converters -->
            <bean class="org.springframework.http.converter.StringHttpMessageConverter"/>
            <bean class="org.springframework.http.converter.FormHttpMessageConverter"/>
            <bean class="org.springframework.http.converter.ByteArrayHttpMessageConverter" />
            <bean class="org.springframework.http.converter.xml.SourceHttpMessageConverter"/>
            <bean class="org.springframework.http.converter.BufferedImageHttpMessageConverter"/>
            <bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter" />
        </list>
    </property>
</bean>

的index.jsp： -

<a href="j_spring_openid_security_check?openid_identifier=https://www.google.com/accounts/o8/id">Login via Google</a><br></br>

通过任何Open ID Provider登录

的applicationContext-security.xml文件

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:sec="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans 

http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 

http://www.springframework.org/schema/security 

http://www.springframework.org/schema/security/spring-security-3.0.xsd">

<http auto-config="true" use-expressions="true">
    <intercept-url pattern="/**" access="permitAll" />
    <openid-login>
        <attribute-exchange>
              <openid-attribute name="email" type="http://axschema.org/contact/email" required="true" />
              <openid-attribute name="fullname" type="http://axschema.org/namePerson" />
              <openid-attribute name="first" type="http://axschema.org/namePerson/first" />
              <openid-attribute name="last" type="http://axschema.org/namePerson/last" />
        </attribute-exchange>
    </openid-login>
    <logout />
</http>

</beans:beans>

任何人都可以指导我，如果我犯了任何错误或帮助我解决一些问题！春天的openId是否还有其他要求

Answer 1

您需要确保在类路径中具有spring-security-web和servlet apis。例如，如果您使用的是Maven，则可以确保pom.xml中包含以下内容：

<dependency>
  <groupId>org.springframework.security</groupId>
  <artifactId>spring-security-config</artifactId>
  <version>3.1.3.RELEASE</version>
  <scope>compile</scope>
</dependency>
<dependency>
  <groupId>org.springframework.security</groupId>
  <artifactId>spring-security-web</artifactId>
  <version>3.1.3.RELEASE</version>
  <scope>compile</scope>
</dependency>
<dependency>
  <groupId>javax.servlet.jsp</groupId>
  <artifactId>jsp-api</artifactId>
  <version>2.1</version>
  <scope>provided</scope>
</dependency>

试图在spring中集成openId但是给出了BeanDefinitionParsingException

1 个答案: