如果队列$ name ==“已经存在”那么

Question

是不是可能，我检查直到队列中的名字？

b=1      
 read -p "Enter how much databases you want to install: " COUNTER
    until [ ${a} -eq ${COUNTER} ]; do

    a=$((a+1))


    echo "What is the name for the $((b++)) database ?"
        read name

    if [ $name == "already there" ]; then
    echo " Please, don't use the same name for a database!"
    exit 1
    else
    :
    fi

我想，当名称已经存在时，脚本会退出...

任何想法？

Answer 1

使用双括号括起条件或双引号变量：

if [[ $name == "already there" ]]; then
    echo " Please, don't use the same name for a database!"
    exit 1
else
    #...
fi

或

if [ "$name" == "already there" ]; then
    echo " Please, don't use the same name for a database!"
    exit 1
else
    #...
fi

Answer 2

已更新

您需要将输入的名称保存到数组中，并检查新插入的名称是否在那里。数组数组检查来自这里。 Check if an array contains a value

#!/bin/bash

has_element ()
{
  local e
  for e in "${@:2}"; do [[ "$e" == "$1" ]] && return 0; done
  return 1
}

b=1
read -p "Enter how much databases you want to install: " COUNTER

let -a CONTAINER

a=0
until [ ${a} == ${COUNTER} ]
do
    a=$((a+1))

    echo "What is the name for the $((b++)) database ?"
    read name


    if has_element "$name" "${CONTAINER[@]}"
    then
        echo "already has"
        exit
    fi

    CONTAINER+=($name)

done

原稿。答案

我想你差不多了。修改了一些错误。

b=1
read -p "Enter how much databases you want to install: " COUNTER

a=0
until [ ${a} == ${COUNTER} ]
do
    a=$((a+1))

    echo "What is the name for the $((b++)) database ?"
    read name

    if [ "$name" == "already there" ]
    then
        echo " Please, don't use the same name for a database!"
        exit 1
    else
        echo "stay..."
    fi

done