我可以获取最新的文件信息属性
var Filepath = directory.GetFiles("myPattern").OrderByDescending(f => f.LastWriteTime).First();
HttpPostedFile myFile = Filepath;
如何阅读此文件的内容? 错误:无法将文件信息转换为文件 下面是具有属性的类文件我试图将最新文件分配给下面的类文件。 HttpPostedFile myFile = Fileupload1.postedfile; //不抛错误 HttpPostedFile myFile = Filepath; //投掷错误 错误:无法将文件信息转换为文件
public sealed class HttpPostedFile
{
// Summary:
// Gets the size of an uploaded file, in bytes.
//
// Returns:
// The file length, in bytes.
public int ContentLength { get; }
//
// Summary:
// Gets the MIME content type of a file sent by a client.
//
// Returns:
// The MIME content type of the uploaded file.
public string ContentType { get; }
//
// Summary:
// Gets the fully qualified name of the file on the client.
//
// Returns:
// The name of the client's file, including the directory path.
public string FileName { get; }
//
// Summary:
// Gets a System.IO.Stream object that points to an uploaded file to prepare
// for reading the contents of the file.
//
// Returns:
// A System.IO.Stream pointing to a file.
public Stream InputStream { get; }
// Summary:
// Saves the contents of an uploaded file.
//
// Parameters:
// filename:
// The name of the saved file.
//
// Exceptions:
// System.Web.HttpException:
// The System.Web.Configuration.HttpRuntimeSection.RequireRootedSaveAsPath property
// of the System.Web.Configuration.HttpRuntimeSection object is set to true,
// but filename is not an absolute path.
public void SaveAs(string filename);
}
答案 0 :(得分:0)
FileInfo
类和文件内容之间存在差异。您可以使用StreamReader
方法通过FileInfo.OpenText
访问文件的内容。
var fileInfo = directory.GetFiles("myPattern")
.OrderByDescending(f => f.LastWriteTime)
.First();
using (StreamReader sr = fileInfo.OpenText()) {
String s = sr.ReadToEnd();
}
答案 1 :(得分:0)
假设您正在阅读文本文件
String text = File.ReadAllText(Directory.GetFiles("myPattern").OrderByDescending(f => File.GetLastAccessTime(f)).First());
答案 2 :(得分:0)
Filepath
是FileInfo
对象,您无法将其设置为HttpPostedFile
FileInfo file = directory.GetFiles("myPattern").OrderByDescending(f => f.LastWriteTime).First();
if (file != null)
string contents = File.ReadAllText(file.FullName);
答案 3 :(得分:-1)
我通过以下代码获得了所需的解决方案:
var myFile = Directory.GetFiles("。")。OrderByDescending(f => F).FirstOrDefault();