Question

下面是我使用cURL将变量传递给另一台服务器的一段代码。虽然与其他服务器有联系，但显示传递的变量 username = null等。如果真的很感激你的建议。提前致谢

if(!isset($_COOKIE['admin'])){

    include_once("login.php");

    echo ("<div id='quote'>Error: Can not access page.");   }

else {       if (isset($_GET['user']) && ($_GET['user'] != "") &&
isset($_GET['pass']) && ($_GET['pass']  != "") && isset($_GET['to'])
&& ($_GET['to'] != "") && ($_GET['username'] != "")) {

                    $username = $_GET["username"]; 

        $idlicenza= $_GET["user"];

        $licence = $_GET["pass"];

                    $to = $_GET["to"];
                    $acc = new Account;

                    $acc->changeVis($idlicenza, $licence, $to);             header("Location: search.php?user=".$username); 




                $ch = curl_init();

            curl_setopt($ch, CURLOPT_URL,"http://xxxx/add-user");

            curl_setopt($ch, CURLOPT_POST, 1);

            curl_setopt($ch, CURLOPT_POSTFIELDS,
                                      "username=userId&idliscence=codes&myid=password");

                // receive server response ...

            curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

            $server_output = curl_exec ($ch);

            print_r($server_output);

            curl_close ($ch);
                    }    } ?>

CURL传递value = null

0 个答案: