Question

上传的文件将存储在数据库和文件夹中（文件夹名称：上传）。现在我想知道如何从数据库/文件夹创建下载文件。我有两个文件butangDonload.php和download.php。当用户点击“donload”字样时，弹出框将出现并保存文件。

butangDonload.php

<?php

    $file = "Bang.png"; //Let say If I put the file name Bang.png
    echo "<a href='download.php?nama=".$file."'>donload</a> ";

?>

的download.php

<?php
    $name= $_GET['nama'];
    download($name);

    function download($name) {
        $file = $nama_fail;

        if (file_exists($file)) {
            header('Content-Description: File Transfer');
            header('Content-Type: application/octet-stream');
            header('Content-Disposition: attachment; filename='.basename($file));
            header('Content-Transfer-Encoding: binary');
            header('Expires: 0');
            header('Cache-Control: must-revalidate');
            header('Pragma: public');
            header('Content-Length: ' . filesize($file));
            ob_clean();
            flush();
            readfile($file);
            exit;
        }
    }
?>

Answer 1

我已经更改为您的代码，只需稍加修改即可。这是代码：

butangDonload.php

<?php
$file = "logo_ldg.png"; //Let say If I put the file name Bang.png
echo "<a href='download1.php?nama=".$file."'>download</a> ";
?>

的download.php

<?php
$name= $_GET['nama'];

    header('Content-Description: File Transfer');
    header('Content-Type: application/force-download');
    header("Content-Disposition: attachment; filename=\"" . basename($name) . "\";");
    header('Content-Transfer-Encoding: binary');
    header('Expires: 0');
    header('Cache-Control: must-revalidate');
    header('Pragma: public');
    header('Content-Length: ' . filesize($name));
    ob_clean();
    flush();
    readfile("your_file_path/".$name); //showing the path to the server where the file is to be download
    exit;
?>

在这里，您需要显示要下载文件的路径。即只提供文件名，但需要提供用于读取该文件的文件路径。所以，它应该被替换为我已经通过使用您的代码进行了测试，修改也将有效。

Answer 2

这里是下载文件的代码，下载了多少％

<?php
$ch = curl_init();
$downloadFile = fopen( 'file name here', 'w' );
curl_setopt($ch, CURLOPT_URL, "file link here");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_BUFFERSIZE, 65536);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_PROGRESSFUNCTION, 'downloadProgress'); 
curl_setopt($ch, CURLOPT_NOPROGRESS, false);
curl_setopt( $ch, CURLOPT_FILE, $downloadFile );
curl_exec($ch);
curl_close($ch);

function downloadProgress ($resource, $download_size, $downloaded_size, $upload_size, $uploaded_size) {

    if($download_size!=0){
    $percen= (($downloaded_size/$download_size)*100);
    echo $percen."<br>";

}

}
?>

Answer 3

您可以使用html5标签直接下载图片

<?php
$file = "Bang.png"; //Let say If I put the file name Bang.png
echo "<a href='download.php?nama=".$file."' download>donload</a> ";
?>

有关详细信息，请查看此链接 http://www.w3schools.com/tags/att_a_download.asp

Answer 4

butangDonload.php

$file = "Bang.png"; //Let say If I put the file name Bang.png
$_SESSION['name']=$file;

试试这个，

<?php

$name=$_SESSION['name'];
download($name);

function download($name){
$file = $nama_fail;
?>

Answer 5

You can also use the following code:

<?php
$filename = $_GET["nama"];
$contenttype = "application/force-download";
header("Content-Type: " . $contenttype);
header("Content-Disposition: attachment; filename=\"" . basename($filename) . "\";");
readfile("your file uploaded path".$filename);
exit();
?>

Answer 6

function downloadFiles($dir, $file) {
    header("Content-type: application/force-download");
    header('Content-Disposition: inline; filename="' . $dir . $file . '"');
    header("Content-Transfer-Encoding: Binary");
    header("Content-length: " . filesize($dir . $file));
    header('Content-Type: application/octet-stream');
    header('Content-Disposition: attachment; filename="' . $file . '"');
    readfile("$dir$file");
}

$dir = "folder_path";

$file = "image_name.jpg";
$download = downloadFiles($dir,$file);

试试这个方法，对我很有帮助。

如何使用php从数据库/文件夹下载文件

6 个答案: