Question

除了糟糕的格式之外，为什么不能将它们打印出来一次。我不认为我正确地将它存储在数组中。所以，如果你们可以帮我解决我的错误，我将不胜感激

import java.util.*;

public class LetCount {

    public static final int NUMCHARS = 26 + 1; //You define

    public static int addr(char ch) {
        return (int) ch - (int) 'A' + 1;
    }

    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in); // for reading input
        int[] count = new int [NUMCHARS];
        int curIndex = 0;
        int max = 0;
        System.out.println("Enter text to be read");
        while (keyboard.hasNext()) {
            String str1 = keyboard.nextLine().toUpperCase();
            char ch = str1.charAt(curIndex);
            for(curIndex = 0; curIndex < str1.length(); curIndex++) {
                ch = str1.charAt(curIndex);
                if (ch >= 'A' && ch <= 'Z') {
                    addr(ch);
                    count[ch - 'A']++;
                }

                for (int i = 0; i > 26; ++i) {
                    int highest;
                    highest = count[i];

                    System.out.printf(" %c ", i + 'A');
                    System.out.println("occurred " + count[i] + " times");
                    if (highest >= max) {
                        if (highest > max) {
                            max = highest;
                        } 
                    }  
                }

                System.out.println(max);
            }
        } 
    }   
}

Answer 1

您的代码中有几个问题：

您正在计算字符串长度次数。
您的for loop读取此内容：for (int i = 0; i > 26; ++i) {应该是for (int i = 0; i < 26; ++i) {
您正在打印整个数组字符串的长度。
您不再需要使用addr功能。

以下是更正后的代码：

import java.util.*;

public class LetCount {

public static final int NUMCHARS = 26 + 1; //You define

public static int addr(char ch) {
    return (int) ch - (int) 'A' + 1;
}

public static void main(String[] args) {
    Scanner keyboard = new Scanner(System.in); // for reading input
    int[] count = new int [NUMCHARS];
    int curIndex = 0;
    int max = 0;
    System.out.println("Enter text to be read");
    while (keyboard.hasNext()) {
        String str1 = keyboard.nextLine().toUpperCase();
        char ch = str1.charAt(curIndex);
        for(curIndex = 0; curIndex < str1.length(); curIndex++) {
            ch = str1.charAt(curIndex);
            if (ch >= 'A' && ch <= 'Z') {
              //  addr(ch); No need to use this
                count[ch - 'A']++;
            }

        }
        int highest;
            for (int i = 0; i < 26; ++i) {   //you had the < sign wrong here.

                highest = count[i];
                if (highest >= max) {
                    if (highest > max) {
                        max = highest;
                    } 
                }  
            } 
            //print the entire thing only once.
            for (int i = 0; i < 26; ++i) {
                System.out.printf(" %c ", i + 'A');
                System.out.println("occurred " + count[i] + " times");
             }

            System.out.println("Maximum is " + max);
          } 
    }   
}

计算文本中的字母并打印计数加上最高和最低

1 个答案: