Question

我正在尝试将我的数据编码为JSON并将其发送到php文件（然后发送到远程数据库）。调用insertmatch时，我希望首先使用contentvalues将值放入SQLite表中，然后将相同的值更改为要发送的JSON。但是我继续遇到未处理的异常错误，当我使用try catch或处理异常时，它会说不使用局部变量响应的值。

关于如何解决这个问题的任何想法？

public long insertMatch(Match match) {
    //returns the id of the inserted row; if an error occurs it returns -1 
    ContentValues values = new ContentValues();
    values.put(DatabaseHelper.KEY_TEAM1, match.getTeam1());
    values.put(DatabaseHelper.KEY_TEAM2, match.getTeam2());
    values.put(DatabaseHelper.KEY_SCORE_TEAM1, match.getScoreTeam1());
    values.put(DatabaseHelper.KEY_SCORE_TEAM2, match.getScoreTeam2());
    values.put(DatabaseHelper.KEY_START_TIME_STAMP, match.getStartTime());
    values.put(DatabaseHelper.KEY_END_TIME_STAMP, match.getEndTime());
    values.put(DatabaseHelper.KEY_LOCATION, match.getLocation());
    Log.d(TAG,"insertMatch: " + values);          

    DefaultHttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://myhost/data.php");

    try {
        String team_1 = match.getTeam1();
        String team_2 = match.getTeam2();
        int  score_team_1= match.getScoreTeam1();
        int score_team_2 = match.getScoreTeam2(); 
        long start_time = match.getStartTime();
        long end_time = match.getEndTime();

        Log.d(TAG,"Checking if values ok for jsoning on " + team_1);
        Log.d(TAG,"Checking if values ok for jsoning on " + team_2);
        Log.d(TAG,"Checking if values ok for jsoning on " + score_team_1);
        Log.d(TAG,"Checking if values ok for jsoning on" + score_team_2);
        Log.d(TAG,"Checking if values ok for jsoning on " + start_time);
        Log.d(TAG,"Checking if values ok for jsoning on " + end_time);

        String jString = "{\"Necessary??Perhaps, perhaps not. Only time will tell\": { \"team_1\": \""+team_1 + "\",\"team_2\":\""+team_2+"\",\"score_team_1\":\""+score_team_1+"\",\"score_team_2\":\""+score_team_2+"\",\"start_time\":\""+start_time+"\",\"end_time\":\""+end_time+"\"}}";

        List <NameValuePair> nvps = new ArrayList <NameValuePair>();
        nvps.add(new BasicNameValuePair("value", jString));
        httppost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));                 
    } catch (UnsupportedEncodingException e) {
        throw new AssertionError("UTF-8 not supported");
    }
    HttpResponse response;//error either here
    response = httpclient.execute(httppost); //or here
    return db.insert(DatabaseHelper.DATABASE_TABLE, null,values);
}

Answer 1

您应该复制/粘贴整个错误，因为您没有提供太多信息。

无论如何，通知一个未使用的局部变量是一个奇怪的异常，因为那更可能是一个回归，但无论如何，如果你不使用变量响应，你就不必声明它。所以你的行

 HttpResponse response; 
 response = httpclient.execute(httppost);

应该只是

 httpclient.execute(httppost);

无论如何，我认为错误是其他的，可能是你如何构建httpost变量。来自logcat的完整信息将有所帮助。

未处理的异常或未使用的局部变量

1 个答案: