获取Android设备的所有者名称

时间：2013-12-03 20:00:36

标签： java android

以下代码适用于模拟器，但无法在Samsung Galaxy S III上运行。

    final String[] projection = new String[]
    { ContactsContract.Profile.DISPLAY_NAME };
    String name = null;
    final Uri dataUri = Uri.withAppendedPath(ContactsContract.Profile.CONTENT_URI, ContactsContract.Contacts.Data.CONTENT_DIRECTORY);
    final ContentResolver contentResolver = getContentResolver();
    final Cursor c = contentResolver.query(dataUri, projection, null, null, null);

    try
    {
        if (c.moveToFirst())
        {
            name = c.getString(c.getColumnIndex(ContactsContract.Profile.DISPLAY_NAME));
        }
    }
    finally
    {
        c.close();
    }
    System.out.println(name);

以下是例外：

12-03 20:57:15.751: E/AndroidRuntime(28172): FATAL EXCEPTION: main
12-03 20:57:15.751: E/AndroidRuntime(28172): java.lang.RuntimeException: Unable to start activity ComponentInfo{ht.smca.flashligh/ht.smca.flashligh.MainActivity}: java.lang.NullPointerException
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2100)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2125)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.access$600(ActivityThread.java:140)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1227)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.os.Handler.dispatchMessage(Handler.java:99)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.os.Looper.loop(Looper.java:137)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.main(ActivityThread.java:4898)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at java.lang.reflect.Method.invokeNative(Native Method)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at java.lang.reflect.Method.invoke(Method.java:511)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1006)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:773)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at dalvik.system.NativeStart.main(Native Method)
12-03 20:57:15.751: E/AndroidRuntime(28172): Caused by: java.lang.NullPointerException
12-03 20:57:15.751: E/AndroidRuntime(28172):    at com.android.internal.os.LoggingPrintStream.println(LoggingPrintStream.java:298)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at ht.smca.flashligh.MainActivity.onCreate(MainActivity.java:68)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.Activity.performCreate(Activity.java:5206)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1083)
12-03 20:57:15.751: E/AndroidRuntime(28172):    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2064)
12-03 20:57:15.751: E/AndroidRuntime(28172):    ... 11 more

有什么建议吗？我这样做是出于学习目的，即研讨会。

5 个答案:

答案 0 :(得分：24)

这将帮助您获取存储在设备上的所有者名称：

Cursor c = getApplication().getContentResolver().query(ContactsContract.Profile.CONTENT_URI, null, null, null, null); 
c.moveToFirst();
textView.setText(c.getString(c.getColumnIndex("display_name")));
c.close();

确保在清单中添加此权限：

<uses-permission android:name="android.permission.READ_CONTACTS"/>

答案 1 :(得分：5)

您有java空指针异常，因此name为null。将您的system.out.println（）放入try中，您将不会遇到此错误。获得名字之后，我真的不知道 - Clad

不是我的帖子，但你的答案是： Get Android Device Name（对于Android设备模型，我的坏）

 android.os.Build.MODEL;

以下是两种方法：

How can I get the google username on Android?

How can I get the first name (or full name) of the user of the phone?

答案 2 :(得分：3)

ContentResolver cr=getContentResolver();
Cursor curser = cr.query(ContactsContract.Profile.CONTENT_URI, null, null, null, null);
if(curser.getCount()>0){
    c.moveToFirst();
    String name=curser.getString(curser.getColumnIndex(
        ContactsContract.Profile.DISPLAY_NAME));
    Toast.makeText(MainActivity.this, "name"+name, Toast.LENGTH_SHORT).show();
}
c.close();

答案 3 :(得分：2)

此代码将为所有者提供完整信息

试试这段代码：

public class EmailFetcher{

    static String getName(Context context) {
        Cursor CR = null;
        CR = getOwner(context);
        String id = "", name = "";
        while (CR.moveToNext())
        {
            name = CR.getString(CR.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
        }
        return name;
    }


    static String getEmailId(Context context) {
        Cursor CR = null;
        CR = getOwner(context);
        String id = "", email = "";
        while (CR.moveToNext()) {
            id = CR.getString(CR.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID));
            email = CR.getString(CR.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
        }
        return email;
    }


    static Cursor getOwner(Context context) {
        String accountName = null;
        Cursor emailCur = null;
        AccountManager accountManager = AccountManager.get(context);
        Account[] accounts = accountManager.getAccountsByType("com.google");
        if (accounts[0].name != null) {
            accountName = accounts[0].name;
            String where = ContactsContract.CommonDataKinds.Email.DATA + " = ?";
            ArrayList<String> what = new ArrayList<String>();
            what.add(accountName);
            Log.v("Got account", "Account " + accountName);
            for (int i = 1; i < accounts.length; i++) {
                where += " or " + ContactsContract.CommonDataKinds.Email.DATA + " = ?";
                what.add(accounts[i].name);
                Log.v("Got account", "Account " + accounts[i].name);
            }
            String[] whatarr = (String[])what.toArray(new String[what.size()]);
            ContentResolver cr = context.getContentResolver();
            emailCur = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null, where, whatarr, null);
            if (id != null) {
                // get the phone number
                Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]{id}, null);
                while (pCur.moveToNext())
                {
                    phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                    Log.v("Got contacts", "phone" + phone);
                }
                pCur.close();
            }
        }
        return emailCur;
    }
}

答案 4 :(得分：0)

ContentResolver cr=getContentResolver();
Cursor curser = cr.query(ContactsContract.Profile.CONTENT_URI, null, null, null, null);
if(curser.getCount()>0){
    c.moveToFirst();
    String name=curser.getString(curser.getColumnIndex(
        ContactsContract.Profile.DISPLAY_NAME));
    Toast.makeText(MainActivity.this, "name"+name, Toast.LENGTH_SHORT).show();
}
c.close();

使用上面的代码从android设备获取所有者名称。基本上，这将为我的用户获取存储在联系人中的姓名。

注意：少数用户会遇到以下异常情况

android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0 at android.database.AbstractCursor.checkPosition(AbstractCursor.java:460) at android.database.AbstractWindowedCursor.checkPosition(AbstractWindowedCursor.java:136) at android.database.AbstractWindowedCursor.getString(AbstractWindowedCursor.java:50) at android.database.CursorWrapper.getString(CursorWrapper.java:137)

此异常不是特定于电话或特定于用户的。某些用户未在联系人列表中设置自己的联系人。因此，为解决此问题，启动应用程序的用户需要在“联系人”应用程序中设置第一行即ME联系人。只要在个人信息中输入您的姓名，就会生成卡。

@Leejjon ^^

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