Question

我是Python的新手，我遇到了一些问题。我有一个包含以下信息的文本文件：

[Name, Start Time, Finish Time]

Xantippe 09:00 11:00
Erica 10:00 12:06
Marcia 09:30 11:45
Elizabeth 10:15 12:10
Angela 11:30 13:45
Freda 12:00 14:20
Maria 12:30 14:10

我需要能够读取文本文件，获取每个人的开始和结束时间，计算时差并将信息写入按升序排列时间的文件中。我有标准方法来计算两次之间的时差，并按如下方式对信息进行排序，但是我无法从文本文件中识别时间并执行任务。有人可以帮忙吗？

import datetime as dt


class TimeCalc:
    start = "09:35:23"
    end = "10:23:00"
    start_dt = dt.datetime.strptime(start, '%H:%M:%S')
    end_dt = dt.datetime.strptime(end, '%H:%M:%S')
    diff = (end_dt - start_dt)
    diff.seconds / 60

    print(diff)

with open('Lad.txt') as fin:
    lines = [line.split() for line in fin]

    from operator import itemgetter
lines.sort(key=itemgetter(2), reverse=True)

with open('sortdesc.txt', 'w') as fout:
    for el in lines:
        fout.write('{0}\n'.format(' '.join(el)))

Answer 1

我不完全清楚你的格式。对于逗号分隔和时间12:00:00，这应该有效：

from datetime import datetime

def time_diff(start, end):
    start_dt = datetime.strptime(start, '%H:%M:%S')
    end_dt = datetime.strptime(end, '%H:%M:%S')
    diff = (end_dt - start_dt)
    return diff.seconds

scores = {}
with open('input.txt') as fin:
    for line in fin.readlines():
        values = line.split(',')
        scores[values[0]] = time_diff(values[1],values[2])

with open('sorted.txt', 'w') as fout:
    for key, value in sorted(scores.iteritems(), key=lambda (k,v): (v,k)):
        fout.write('%s,%s\n' % (key, value))

Python - 计算文本文件的时差

1 个答案: