我有一个程序可以读取下面这样的文件：
12 9-62-1
Sample Name: 9-62-1 Injection Volume: 25.0
Vial Number: 37 Channel: ECD_1
Sample Type: unknown Wavelength: n.a.
Control Program: Anions Run Bandwidth: n.a.
Quantif. Method: Anions Method Dilution Factor: 1.0000
Recording Time: 10/2/2013 19:55 Sample Weight: 1.0000
Run Time (min): 14.00 Sample Amount: 1.0000
No. Ret.Time Peak Name Height Area Rel.Area Amount Type
min µS µS*min % mG/L
1 2.99 Fluoride 7.341 1.989 0.87 10.458 BMB
2 3.88 Chloride 425.633 108.551 47.72 671.120 BMb
3 4.54 Nitrite 397.537 115.237 50.66 403.430 bMB
4 5.39 n.a. 0.470 0.140 0.06 n.a. BMB
5 11.22 Sulfate 4.232 1.564 0.69 13.064 BMB
Total: 835.213 227.482 100.00 1098.073
我需要让它输出如下结果：
Sample#,Date,Time,Peak Name,Amount
9-62-1,10/2/2013,19:55,Fluoride,10.458,
9-62-1,10/2/2013,19:55,Chloride,671.120,
9-62-1,10/2/2013,19:55,Nitrite,403.430,
9-62-1,10/2/2013,19:55,Sulfate,13.064,
基本上包括每个峰值名称和金额的相同样本＃，日期和时间。
我目前的结果是这样的：
Sample#,Date,Time,Peak Name,Amount
9-62-1,10/2/2013,19:55,Fluoride,10.458,
Chloride,671.120,
Nitrite,403.430,
Sulfate,13.064,
它打印第二行好，但对于其他行，它不会打印样本＃，日期和时间。
我该如何解决这个问题？ 谢谢！
这是我的代码：
try
{
Scanner input = new Scanner(new FileReader(selectFile.getSelectedFile()));
System.out.println("Sample#,Date,Time,Peak Name,Amount");
int linesToSkip = 29;
BufferedReader br = new BufferedReader(new FileReader(selectFile.getSelectedFile()));
String line;
while ( (line = br.readLine()) != null) {
if (--linesToSkip > 0) {
continue;
}
if (line.isEmpty() || line.trim().equals("") || line.trim().equals("\n")) {
continue;
}
if (line.contains("n.a.")) {
continue;
}
if (line.contains("Total")) {
continue;
}
if (line.startsWith("Name:")) {System.out.print(input.next());}
String[] values = line.split("\t");
int index = 0;
for (String value : values) {
/*System.out.println("values[" + index + "] = " + value);*/
index++;
}
while (input.hasNext()) {
String word = input.next();
Pattern pattern1 = Pattern.compile("Name:");
Pattern pattern2 = Pattern.compile("Time:");
Matcher matcher1 = pattern1.matcher(word);
Matcher matcher2 = pattern2.matcher(word);
Matcher matcher3 = pattern2.matcher(word);
if(matcher1.matches()){
System.out.print(input.next() + ",");
}
if(matcher2.matches()){
System.out.print(input.next() + ",");
}
if(matcher3.matches()){
System.out.print(input.next() + ",");
}
}
System.out.print(values[2]+",");
System.out.println(values[6]+"\b,");
}
br.close();
}
catch(IOException e)
{
System.out.println("The file cannot be read");
}
答案 0 :(得分：1)
我不得不对您的程序进行一些更改，我必须将文本文件选项卡分隔为您的程序所期望的。我希望这会对你有所帮助：
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Reader {
private static String lineHolder;
public static void main(String [] args) throws IOException{
try
{
String sampleNamefile="/tmp/two.txt";
/*Sample Name: 9-62-1 Injection Volume: 25.0
*/
String noFile="/tmp/oneNew.txt";
/* No. Ret.Time Peak Name Height Area Rel.Area Amount Type
min µS µS*min % mG/L
*/
File inputFile = new File(sampleNamefile);
// Scanner input = new Scanner(new FileReader(selectFile.getSelectedFile()));
Scanner input = new Scanner(inputFile);
System.out.println("Sample#,Date,Time,Peak Name,Amount");
int linesToSkip = 29;
File outputFile2 = new File(noFile);
//BufferedReader br = new BufferedReader(new FileReader(selectFile.getSelectedFile()));
BufferedReader br = new BufferedReader(new FileReader(noFile));
String line;
while ( (line = br.readLine()) != null) {
/* if (--linesToSkip > 0) {
continue;
}*/
if (line.isEmpty() || line.trim().equals("") || line.trim().equals("\n")) {
continue;
}
if (line.contains("n.a.")) {
continue;
}
if (line.contains("Total")) {
continue;
}
if (line.startsWith("Name:")) {System.out.print(input.next());}
String[] values = line.split("\t");
int index = 0;
for (String value : values) {
// System.out.println("values[" + index + "] = " + value);
index++;
}
while (input.hasNext()) {
String word = input.next();
Pattern pattern1 = Pattern.compile("Name:");
Pattern pattern2 = Pattern.compile("Time:");
Matcher matcher1 = pattern1.matcher(word);
Matcher matcher2 = pattern2.matcher(word);
Matcher matcher3 = pattern2.matcher(word);
if(matcher1.matches()){
//System.out.print(input.next() + ",");
lineHolder=input.next()+ "," ;
}
if(matcher2.matches()){
//System.out.print(input.next() + ",");
lineHolder+=input.next() + ",";
}
if(matcher3.matches()){
// System.out.print(input.next() + ",");
lineHolder+=input.next()+ "," ;
}
}
if(!line.contains("No. ") ){
if(!line.contains("min") ){
System.out.print(lineHolder);
System.out.print(values[2]+",");
System.out.println(values[6]+"\b,");
}
}
}
br.close();
}finally{
}
}
}
结果如下： 样品＃，日期，时间，峰名，金额
9-62-1,10/2/2013,19:55,Fluoride,10.458,
9-62-1,10/2/2013,19:55,Chloride,671.120,
9-62-1,10/2/2013,19:55,Nitrite,403.430,
9-62-1,10/2/2013,19:55,Sulfate,13.064,