Question

我正在尝试关注Simple Blog tutorial at Django By Example。我已经设法生成一个正确加载的网站，但是当索引视图加载查找，并且各个帖子的链接显示并且看起来格式正确时，它们指向索引模板，所以所有单击它们时发生的是它重新加载索引视图。我是Django的新手，教程很少，至少可以说是因为它是为旧版本的Django编写的，而我使用的是1.5。我整个下午一直在盯着它，我很迷茫。

这是我的urls.py

from django.conf.urls import patterns, url

from blog import views

urlpatterns = patterns('blog.views',
#index
   (r"$", 'main'),
   #ex: /1/
   (r"^(\d+)/$", 'post'),
   #ex: /add_comment/1/
   (r"^add_comment/(\d+)/$", 'add_comment'),
)

my views.py

from blog.models import Post, PostAdmin, Comment, CommentAdmin

class CommentForm(ModelForm):
class Meta:
    model = Comment
    exclude = ["post"]

def main (request):
"""Main Listing."""
posts = Post.objects.all().order_by("-created")
paginator = Paginator(posts, 10)

try: page = int(request.GET.get("page", '1'))
except ValueError: page = 1

try:
    posts = paginator.page(page)
except (InvalidPage, EmptyPage):
    posts = patinator.page(paginator.num_pages)

return render_to_response("blog/list.html", dict(posts=posts, user=request.user))


def post (request, pk):
"""single post with comments and comment form"""
post = Post.objects.get(pk=int(pk))
comments = Comment.objects.filter(post=post)
d = dict(post=post, comments=comments, form=CommentForm(), user=request.user)
d.update(csrf(request))
return render_to_response("blog/post.html", d)

以及包含不在任何地方的链接的list.html！

{% extends "blog/bbase.html" %}

{% block content %}
<div class="main">

    <!-- Posts  -->
    <ul>
        {% for post in posts.object_list %}
            <div class="title">{{ post.title }}</div>
            <ul>
                <div class="time">{{ post.created }}</div>
                <div class="body">{{ post.body|linebreaks }}</div>
                <div class="commentlink"><a href="{% url 'blog.views.post' post.pk %}">Comments</a></div>
            </ul>
        {% endfor %}
    </ul>

    <!-- Next/Prev page links  -->
    {% if posts.object_list and posts.paginator.num_pages > 1 %}
    <div class="pagination" style="margin-top: 20px; margin-left: -20px; ">
        <span class="step-links">
            {% if posts.has_previous %}
                <a href= "?page={{ posts.previous_page_number }}">newer entries &lt;&lt; </a>
            {% endif %}

            <span class="current">
                &nbsp;Page {{ posts.number }} of {{ posts.paginator.num_pages }}
            </span>

            {% if posts.has_next %}
                <a href="?page={{ posts.next_page_number }}"> &gt;&gt; older entries</a>
            {% endif %}
        </span>
    </div>
    {% endif %}

</div>

{% endblock %}

Answer 1

Django URL解析器将返回与传入请求匹配的第一个URL模式。 “主要”视图r"$"的正则表达式将匹配任何传入请求，因为您只查找字符串结尾的$。

您需要将“主”网址正则表达式更改为r'^$'。

或者，如果您想要一个全能视图，可以将“主要”视图移动到您的网址底部

URL正确生成但未重定向到正确的模板

1 个答案: