这是我的PHP代码：
class joinTeam
{
//when player joins a team
function join()
{
if((isset($_POST["userID"]) && !is_null($_POST["userID"])) && (isset($_POST["teamID"]) && !is_null($_POST["teamID"])))
{
$teamID = ($_POST["teamID"]);
$userID = ($_POST["userID"]);
$cEntry = "";
$insertTime = "";
//connect database
$link_id = db_connect();
if(!$link_id)
{
//database error
sendResponse(400, 'Invalid Request');
return false;
}
//unicode data in database
mysql_set_charset("utf8");
//select player teamID and userID
$query = " SELECT c_user_id";
$query .= " , c_team_id";
$query .= " FROM member_status";
$query .= " WHERE c_team_id='".$teamID."'";
$query .= " AND c_user_id='".$userID."'";
$result = mysql_query($query);
$totalRowsCount = mysql_num_rows($result);
//when player does not exists
if($totalRowsCount == 0)
{
//insert player request
$query = " INSERT INTO member_status";
$query .= " (c_team_id";
$query .= " ,c_user_id";
$query .= " ,c_entry";
$query .= " ,dt_insert_time";
$query .= " )";
$query .= " VALUES ('".$teamID."'";
$query .= " ,'".$userID."'";
$query .= " ,'2'";
$query .= " ,'".date('Y-m-d H:i:s')."'";
$query .= " )";
$result1 = mysql_query($query);
if(!$result1)
{
sendResponse(400, 'Insert Fail');
return true;
}
else
{
$returnData = array(
"response" => "Insert Successfull"
);
sendResponse(200, json_encode($returnData));
return true;
}
}
else
{
//select last player status
$query = " SELECT c_user_id";
$query .= " , c_team_id";
$query .= " , c_entry";
$query .= " , dt_insert_time";
$query .= " FROM member_status";
$query .= " WHERE c_team_id='".$teamID."'";
$query .= " AND c_user_id='".$userID."'";
$query .= "ORDER BY member_status.dt_insert_time DESC";
$query .= " Limit 1";
$result2 = mysql_query($query);
while($row = mysql_fetch_array( $result2))
{
$cEntry = $row["c_entry"];
$teamID = $row["c_team_id"];
$userID = $row["c_user_id"];
$insertTime = $row["dt_insert_time"];
}
switch($cEntry)
{
case "1":
sendResponse(400, 'Already Registered');
return true;
break;
case "2":
sendResponse(400, 'Already Requested');
return true;
break;
case "3":
sendResponse(400, 'Got Request From Team');
return true;
break;
case "4":
//player request send back
$query = " UPDATE member_status";
$query .= " SET c_entry='2'";
$query .= " WHERE c_user_id='".$userID."'";
$query .= " AND c_team_id='".$teamID."'";
$query .= " AND dt_insert_time='".$insertTime."'";
$result3 = mysql_query($query);
if(!$result3)
{
sendResponse(400, 'Insert Fail');
return true;
}
else
{
$returnData = array(
"response" => "Update Successfull"
);
sendResponse(200, json_encode($returnData));
return true;
}
break;
default:
//insert new player request
$query = " INSERT INTO member_status";
$query .= " (c_team_id";
$query .= " ,c_user_id";
$query .= " ,c_entry";
$query .= " ,dt_insert_time";
$query .= " )";
$query .= " VALUES ('".$teamID."'";
$query .= " ,'".$userID."'";
$query .= " ,'2'";
$query .= " ,'".date('Y-m-d H:i:s')."'";
$query .= " )";
$result4 = mysql_query($query);
if(!$result4)
{
sendResponse(400, 'Insert Fail');
return true;
}
else
{
$returnData = array(
"response" => "Insert Successfull"
);
sendResponse(200, json_encode($returnData));
return true;
}
}
}
}
else
{
sendResponse(400, 'Invalid Request');
return true;
}
}
}
//create object
$joinTeam = new joinTeam;
//call method
$joinTeam -> join();
?>
这是我运行这个php时的结果 1.注册成功后，php就这样回归 {“response”：“插入成功”} 我需要显示“成功注册”
2.但是在已经注册的情况下，php会像那样返回 已被请求。我需要显示“你已经请求”
但我不知道如何检查从php返回
这是我的javaCode： public void OnClickForSave（View v）抛出异常{
String result=null;
String response=null;
String memberID="000000011";
String teamID="000008";
ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(2);
postParameters.add(new BasicNameValuePair("teamID",teamID));
postParameters.add(new BasicNameValuePair("userID",memberID));
if(v.getId()==(R.id.imgbtn_layout2))
{
Intent intent = new Intent(this, IntentTesting.class);
startActivity(intent);
}
if(v.getId()==(R.id.imgbtn_lsave)){
if(txt_teamID.getText().toString().trim().equals(null)||txt_teamID.getText().toString().trim().equals(""))
{
AlertDialog empty=createDialogEmpty(this,"Enter Team ID");
empty.show();
txt_teamID.selectAll();
txt_teamID.requestFocus();
}
else if(txt_teamID.getText().toString().trim().length()>6)
{
AlertDialog notFormat=createDialogEmpty(this,"More Than 6 Characters");
txt_teamID.selectAll();
txt_teamID.requestFocus();
notFormat.show();
}
else
{
try {
response=CustomHttpClient.executeHttpPost("http://10.0.2.2/football365/joinTeam.php",postParameters);
//JSONObject jArray = new JSONObject (response);
//Log.i("JSON",jArray+"");
} catch (JSONException e) {
e.printStackTrace();
}
result=response.toString();
checkMessage(response.toString());
Log.i("JSON",result+"");
}
}
}
事实是我不知道如何检索
答案 0 :(得分：0)
我希望这会奏效......
try {
JSONObject json = new JSONObject(response);
String str = json.getString("string_name");
// Toast this String
} catch (JSONException e) {
e.printStackTrace();
}
答案 1 :(得分：0)
在您的SQL语句中，在insert语句的末尾，您应该放置SELECT 'InsertSuccessfull' AS Response。然后，在返回结果的PHP文件中，将此while循环将SQL结果编码为JSON格式：
while($e=mysql_fetch_assoc($q)) /*where $q is mysql_query()*/
$output[]=$e;
print(json_encode($output));
您将收到[{Response:'InsertSuccessfull'}]之类的回复。现在，您可以在应用中检索此内容：
String[] listOfResponses = {};
InputStream is = null;
String result = "";
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("www.mywebservice.com/getAll.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try{
//BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"utf-8"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
// ATTENTION:
listOfResponses[i] = json_data.getString("Response");
}
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
我想我没有遗漏任何东西，但请注意。