Question

我正在使用HttpWebRequest.GetRequestStream连接到Dot Net的其他PHP链接，将一些数据从.Net发送到PHP。但是当控件进入“Stream newrStream = myrRequest.GetRequestStream（）;”行时，它的前两次工作正常。并且从第三次开始延迟了几秒钟。如何解决这个问题。

我的编码是：

ASCIIEncoding Encode = new ASCIIEncoding();
     string postDat = "Name=xxx";
     byte[] datas = Encode.GetBytes(postDat);

HttpWebRequest myrRequest = HttpWebRequest)WebRequest.Create("http://www.xxx.php");
            myrRequest.Method = "POST";
            myrRequest.ContentType = "application/x-www-form-urlencoded";
            myrRequest.ContentLength = datas.Length;
            Stream newrStream = myrRequest.GetRequestStream();

            // Send the data.
            newrStream.Write(datas, 0, datas.Length);
            newrStream.Close();

Answer 1

要记住的第一件事是检查发送的URI，参数和标题，具体来说：

保留字符。通过URI发送保留字符可以带来问题! * ' ( ) ; : @ & = + $ , / ? # [ ]
URI长度：不应超过2000个字符
长度标头：大多数网络服务器都会限制它们的标头大小接受。例如，在Apache默认限制为8KB。

请注意，如果您想要发送较长的数据，建议您在邮件正文中发送：

    string uri = string.Format("https://my-server.com/api/document?queryParameter={1}", "value");
    WebRequest req = WebRequest.Create(uri);
    req.Method = "POST";
    string data = "Some data"; //Body data
    ServicePointManager.Expect100Continue = false;
    using (var streamWriter = new StreamWriter(req.GetRequestStream()))
    {
        streamWriter.Write(data);
        streamWriter.Flush();
        streamWriter.Close();
    }
    HttpWebResponse resp = req.GetResponse() as HttpWebResponse;
    Stream GETResponseStream = resp.GetResponseStream();
    StreamReader sr = new StreamReader(GETResponseStream);
    var response = sr.ReadToEnd(); //Response
    resp.Close(); //Close response
    sr.Close(); //Close StreamReader

对HttpWebRequest.GetRequestStream采取延迟

1 个答案: