Question

如果此行为空，我该怎么办呢？它会显示另一行

假设名称行为空白

echo '<td>' . $row['name'] . '</td>';

因此，如果名称行为空白，则会显示echo '<td>' . $row['companyname'] . '</td>';行

请帮助我如何解决这个问题感谢

        echo "<tr>";
        echo '<td>' . $row['buildingname'] . '</td>';
        echo '<td>' . $row['area'] . '</td>';
        echo '<td>' . $row['city'] . '</td>';
        echo '<td>' . $row['flatno'] . '</td>';
        echo '<td>' . $row['name'] . '</td>';
        echo '<td>' . $row['mobileno'] . '</td>';
        echo '<td>' . $row['agreementdates'] . '</td>';
        echo '<td>' . $row['agreementdatee'] . '</td>';    
        echo "</tr>";

Answer 1

尝试这个我认为这是有效的。

echo '<td>' . empty($row['name']) ? $row['companyname'] : $row['name'] . '</td>';

Answer 2

尝试

if(empty( $row['name'])){
  $tbl = '<td>' . $row['companyname'] . '</td>';
}else{
   $tbl = '<td>' . $row['name'] . '</td>';
}
echo $tbl;

Answer 3

试试这个：

echo "<tr>";
 if(!empty($row['buildingname'])) {
    echo '<td>' . $row['buildingname'] . '</td>';
 }
 if(!empty($row['area'])) {
    echo '<td>' . $row['area'] . '</td>';
 }
 if(!empty($row['city'])) {
    echo '<td>' . $row['city'] . '</td>';
 }
 if(!empty($row['flatno'])) {
    echo '<td>' . $row['flatno'] . '</td>';
 }
 if(!empty($row['name'])) {
    echo '<td>' . $row['name'] . '</td>';
 }
 if(!empty($row['mobileno'])) {
    echo '<td>' . $row['mobileno'] . '</td>';
 }
 if(!empty($row['agreementdates'])) {
    echo '<td>' . $row['agreementdates'] . '</td>';
 }
echo "</tr>";

如果此行为空，则它将显示另一行

3 个答案: