Question

我正在开发一个通过php webservice连接到Mysql数据库的Android应用程序。现在我可以从Mysql数据库中读取数据并将它们添加到我的android sqlite数据库中就好了。

现在我需要将数据的任何更新从数据库推送到应用程序。经过深入研究后，建议的最佳解决方案是GCM，但由于项目中的某些限制，我不允许使用它。任何人都可以提出任何替代方案，请记住，我对这一切都很新。

感谢。

Answer 1

AsyncTask是Android提供的一个抽象类，它可以帮助我们正确使用UI线程。这个类允许我们执行长/后台操作并在UI线程上显示其结果，而不必操纵线程。

您可以使用AsyncTask来调用您的Web服务：

private class LongOperation extends AsyncTask<String, Void, String> {

    @Override
    protected String doInBackground(String... params) {
            try {
                //call your webservice to perform MySQL database opration
                StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
                    .permitAll().build();
                StrictMode.setThreadPolicy(policy);
                HttpClient httpclient = new DefaultHttpClient();
                HttpGet httpget = new Http Get("http://yourserver.com/webservices/service.php?id="
                    + URLEncoder.encode("record_id") +"&param1="
                    + URLEncoder.encode("param1 value") + "&param2="+ URLEncoder.encode("param2 value"));

                HttpResponse response = httpclient.execute(httpget);
                final String str=EntityUtils.toString(response.getEntity());

                myjson = new JSONObject(str);
                //perform JSON parsing to get webservice result.
                if (myjson.has("success") == true) {
                    //Updation is succesful

                } else {
                    //failed to perform updation

                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        return "Executed";
    }

    @Override
    protected void onPostExecute(String result) {
        // This will be executed after completion of webservice call. and `String result` will have returned value from doInBackground()
        // might want to change "executed" for the returned string passed
        // into onPostExecute() but that is upto you

    }

    @Override
    protected void onPreExecute() {}

    @Override
    protected void onProgressUpdate(Void... values) {}
}

现在，通过创建LongOperation类的对象

来执行webservice调用

LongOperation webCall = new LongOperation();
webCall.execute();

在PHP中你应该写如下：

<?php

//DB Connection code:
$dbhost = "server";
$dbuser = "user_name";
$dbpassword = "pass";
$database = "your_db";

// connect to the database
$db = mysql_connect($dbhost, $dbuser, $dbpassword) or die("Connection Error: ".mysql_error());
mysql_select_db($database, $db) or die("Error conecting to db.");

header("Content-type: text/json");

if (!isset($_GET['id']) || $_GET['id'] == "" ||!isset($_GET['param1']) || $_GET['param1'] == "" || !isset($_GET['param2']) || $_GET['param2'] == "" ){
    echo json_encode(array('error' => 'Required arguments missing.'));
    exit;
}
$id = mysql_real_escape_string($_GET['id']); //escape string to prevent SQL injection attack.
$param1 = mysql_real_escape_string($_GET['param1']);
$param2 = mysql_real_escape_string($_GET['param2']);

$sql = "update your_table set param1='$param1',param2='$param2' where id=$id";

mysql_query($sql);

if (mysql_affected_rows()==1) {
    echo json_encode(array('success' => "updated"));
}else{
    echo json_encode(array('error' => "not updated"));
}
?>

您可以使用POST方法将参数传递给webservice以使其更安全。：）

将数据推送到Android应用

1 个答案: