Question

这是我的一段名为汤的HTML代码。它已经是一个BeautifulSoup对象

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        <table class="tabel70" border="0"><tr><!-- table header --><td class="tablecorner"><img src="http://www.addic7ed.com/images/tl.gif" /></td>
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                <td>
<form action="/search.php" method="get">
<div align="center">
<input name="search" type="text" id="search" size="50" value="nikita 03x02" class="inputCool" />&#160;
 <input name="Submit" type="submit" class="coolBoton" value="Search" /><br /><b>1 results found</b> </div><br /><center><br /><form action="https://www.paypal.com/cgi-bin/webscr" method="post">
    <input type="hidden" name="cmd" value="_s-xclick" /><input type="hidden" name="hosted_button_id" value="EC7EPAVR5MXV6" /><input type="image" src="https://www.paypal.com/en_US/i/btn/btn_donateCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!" /><img alt="" border="0" src="https://www.paypal.com/en_US/i/scr/pixel.gif" width="1" height="1" /></form> <br /></center>
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<br /><table class="tabel" align="center" width="80%" border="0"><tr><td><img src="images/television.png" /></td><td><a href="serie/Nikita/3/2/Innocence" debug="68217">Nikita - 03x02 - Innocence</a></td></tr><tr><p>
</p><p>
</p></tr></table></form></td>
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            </tr><tr><!-- table footer --><td class="tablecorner"><img src="http://www.addic7ed.com/images/bl.gif" /></td>
                <td></td>
                <td class="tablecorner"><img src="http://www.addic7ed.com/images/br.gif" /></td>
            </tr></table></div>

我想使用BeautifulSoup和python

从class = tabel获取href（即＆＃34; serie / Nikita / 3/2 / Innocence＆＃34;）

目前我可以使用

提取它

soup.find(attrs = {'class':'tabel'}).find('a')['href']

但这似乎有点令人费解。是否有更简单（pyhonic）的方式来获取此URL？

干杯

Answer 1

试试这个 -

page = urllib2.urlopen(url).read()
link_pat = SoupStrainer('a')
links = BeautifulSoup(page, parseOnlyThese=link_pat)
for link in links:
    url = link['href'].strip('/')

如何使用Python BeautifulSoup从某些html类中获取href

1 个答案: