我开始玩Espresso,让我的基本测试运行。现在试图弄清楚如何检查我的编辑文本是否有特定的提示文本?感谢。
onView(withId(R.id.locationInput)).check(matches...?)
答案 0 :(得分:47)
由于Espresso 2.0只使用内部 ViewMatcher withHint :
onView(withId(R.id.locationInput)).check(matches(withHint("your_hint")))
答案 1 :(得分:19)
看起来我想通了。基本上,您需要创建自己的匹配器:
public static Matcher<View> withHint(final String expectedHint) {
return new TypeSafeMatcher<View>() {
@Override
public boolean matchesSafely(View view) {
if (!(view instanceof EditText)) {
return false;
}
String hint = ((EditText) view).getHint().toString();
return expectedHint.equals(hint);
}
@Override
public void describeTo(Description description) {
}
};
}
然后你可以使用它:
onView(withId(R.id.locationInput)).check(matches(withHint("Location (Optional)")));
答案 2 :(得分:3)
执行此操作的方式略有不同。在我的情况下,在将其传递给匹配器之前检查String是否为null(如Espresso示例中所述)。并且在下面的代码中,您不需要具有此提示的EditText的R.id。您只需检查是否显示带有“hintText”的提示:
import static com.google.common.base.Preconditions.checkArgument;
import static com.google.common.base.Preconditions.checkNotNull;
public final class Matchers {
public static Matcher<View> withItemHint(String hintText) {
// use preconditions to fail fast when a test is creating an invalid matcher.
checkArgument(!(hintText.equals(null)));
return withItemHint(is(hintText));
}
public static Matcher<View> withItemHint(final Matcher<String> matcherText) {
// use preconditions to fail fast when a test is creating an invalid matcher.
checkNotNull(matcherText);
return new BoundedMatcher<View, EditText>(EditText.class) {
@Override
public void describeTo(Description description) {
description.appendText("with item hint: " + matcherText);
}
@Override
protected boolean matchesSafely(EditText editTextField) {
return matcherText.matches(editTextField.getHint().toString());
}
};
}
}
用法:
import static com.google.android.apps.common.testing.ui.espresso.matcher.ViewMatchers.isDisplayed;
import static com.google.android.apps.common.testing.ui.espresso.assertion.ViewAssertions.matches;
import static com.google.android.apps.common.testing.ui.espresso.Espresso.onView;
import static com.your.package.withMatcher.withItemHint;
.
.
.
onView(withItemHint(someHintString)).check(matches(isDisplayed()));
答案 3 :(得分:1)
我创建了一个支持传递resourceId而不是String
的Matcherpublic static Matcher<View> withHint(final int resourceId) {
return new BoundedMatcher<View, TextView>(TextView.class) {
private String resourceName = null;
private String expectedHint = null;
@Override
public boolean matchesSafely(TextView editText) {
if (null == expectedHint) {
try {
expectedHint = editText.getResources().getString(resourceId);
resourceName = editText.getResources().getResourceEntryName(resourceId);
} catch (Resources.NotFoundException ignored) {
/* view could be from a context unaware of the resource id. */
}
}
if (null != expectedHint) {
return expectedHint.equals(editText.getHint());
} else {
return false;
}
}
@Override
public void describeTo(Description description) {
description.appendText("with string from resource id: ");
description.appendValue(resourceId);
if (null != resourceName) {
description.appendText("[");
description.appendText(resourceName);
description.appendText("]");
}
if (null != expectedHint) {
description.appendText(" value: ");
description.appendText(expectedHint);
}
}
};
}
它是由Valera Zakharov(withText(resourceId)指出的Espresso's withText matcher的复制