Question

如何将包含文本字符串的所有数组连接或附加到单个数组中？从以下代码：

    String nList[] = {"indonesia", "thailand", "australia"};

    int nIndex[] = {100, 220, 100};

    String vkList[] = {"wounded", "hurt"};

    int vkIndex[] = {309, 430, 550};

    String skList[] = {"robbed", "detained"};

    int skIndex[] = {120, 225};

    String nationality = "";

    //System.out.println(nationality);

我想存储所有三个包含字符串的数组的所有字符串：

    String nList[] = {"indonesia", "thailand", "australia"};

    String vkList[] = {"wounded", "hurt"};

    String skList[] = {"robbed", "detained"};

成一个数组，比如array1 []。

Answer 1

ArrayList<String> temp = new ArrayList<String>();
temp.addAll(Arrays.asList(nList));
temp.addAll(Arrays.asList(vkList));
temp.addAll(Arrays.asList(skList));

String[] result = (String[])temp.toArray();

Answer 2

您可以将每个数组的内容添加到临时List，然后将其内容转换为String[]。

List<String> temp = new ArrayList<String>();
temp.addAll(Arrays.asList(nList));
temp.addAll(Arrays.asList(vkList));
temp.addAll(Arrays.asList(skList));

String[] result = new String[temp.size()];
for (int i = 0; i < temp.size(); i++) {
    result[i] = (String) temp.get(i);
}

或者，您可以使用Guava的ObjectArrays#concat(T[] first, T[] second, Class< T > type)方法，该方法返回一个包含两个给定数组的连接内容的新数组。例如：

String[] concatTwoArrays = ObjectArrays.concat(nList, vkList, String.class);
String[] concatTheThirdArray = ObjectArrays.concat(concatTwoArrays, skList, String.class);

Answer 3

public static String[] join(String [] ... parms) {
 // calculate size of target array
 int size = 0;
 for (String[] array : parms) {
   size += array.length;
 }

 String[] result = new String[size];

 int j = 0;
 for (String[] array : parms) {
   for (String s : array) {
     result[j++] = s;
   }
 }
return result;
}

只需定义自己的连接方法即可。找到@ http://www.rgagnon.com/javadetails/java-0636.html

如何将多个数组的所有字符串元素连接成一个单独的数组？

3 个答案: