如何在Firefox中使用PURE javascript将所选文本替换为其他文本?
我用这个来选择:
var sel = this.getSelection();
var range = sel.getRangeAt(0);
还有这个重要问题:
我想保留原始格式的字符(当然新字符串将具有正确的格式)
选择可以完成“跨元素”(我的意思是选择可以包含来自一个元素的一些文本,如div或table,以及来自另一个元素的一些文本)。
示例,文档:
<div>
this is a test
</div>
<div>
<b>still a test</b>
</div>
<table style="width:100%;">
<tr>
<td>
another word</td>
<td>
stackoverflow</td>
</tr>
<tr>
<td>
bump</td>
<td>
</td>
</tr>
</table>
用户选择以下文本(通过一个选择):
他的测试仍然是一个测试结果
所以现在我想替换保留格式的文本,例如用new string =
替换所有东西XXX XX X XXXX XXXXX X XXXX XXXX
最终文件(替换后)将是:
<div>
tXXX XX X XXXX
</div>
<div>
<b>XXXXX X XXXX</b>
</div>
<table style="width:100%;">
<tr>
<td>
XXXXher word</td>
<td>
stackoverflow</td>
</tr>
<tr>
<td>
bump</td>
<td>
</td>
</tr>
</table>
答案 0 :(得分:6)
哇,那太可怜了!
<强>的Javascript 强>
var sel, range, nodevalue, startFound, stop;
function goThroughElements(el){
// If el is the start node, set startFound to true
if(el.isSameNode(range.startContainer)) startFound = true;
if(startFound){
// If this is the start node, replace the text like this: abcd[ef gh] --> abcdxx xx
if(el.isSameNode(range.startContainer)){
// \w stands for a word character
nodevalue = el.nodeValue.substring(range.startOffset).replace(/\w/g, 'x');
el.nodeValue = el.nodeValue.substring(0, range.startOffset) + nodevalue;
}
// If this is the end node, replace the value like this: [abc def]gh ij -> xxx xxxgh ij
else if(el.isSameNode(range.endContainer)){
nodevalue = el.nodeValue.substring(0,range.endOffset).replace(/\w/g, 'x');
el.nodeValue = nodevalue + el.nodeValue.substring(range.endOffset);
// Now we can stop
stop = true;
}
// If this is just a text node, replace the value by xxxx
else if(el.nodeType == 3){
el.nodeValue = el.nodeValue.replace(/\w/g, 'x')
}
}
// Loop trough el's brothers
while(el){
// Stop if we need to
if(stop) return;
// If this element has child nodes, call this function again with the first child node
if(el.hasChildNodes()){
goThroughElements(el.childNodes[0]);
}
// Jump to el's brother, or quit the loop
if(el.nextSibling)
el = el.nextSibling;
else
break;
}
}
$(document).ready(function() {
$(this).mouseup(function(){
// Get the selection
sel = window.getSelection();
range = sel.getRangeAt(0);
// Stop must be false if the last selected text node isn't found, startFound must be false when the start isn't found
stop = false; startFound = false;
if(range.collapsed == false){
// Check if the selection takes place inside one text node element
if(range.startContainer.isSameNode(range.endContainer)){
// ab[cdefg]h -> aaxxxxxh
nodevalue = range.startContainer.nodeValue;
range.startContainer.nodeValue = nodevalue.substring(0, range.startOffset) + nodevalue.substring(range.startOffset, range.endOffset).replace(/\w/g, 'x') + nodevalue.substring(range.endOffset);
} else {
// If the start node of the selection isn't the same as the end node, loop through all elements
goThroughElements(range.commonAncestorContainer.childNodes[0]);
}
// Collapse selection.
range.collapse(true);
}
});
});
示例强>
您当然可以try the code
可能它不是最佳解决方案,因为它开始从根搜索起始节点。从range.startContainer
和range.endContainer
的第一个共同父元素进行搜索会更快,但我不知道该怎么做...
修改强>
我将{-1}}中的to-X函数包装起来,并使用if(range.collapsed == false)
来开始迭代选择的开始和结束位置的公共父项的第一个子元素。 p>