我试图在这个方法中使用多个连接来制作一个goup,但它没有给我任何回复
public List<CTarifaAplicada> get_TarifasAplicadas(int id_proforma)
{
var pt = (from ta in db.TarifaAplicada
where ta.IDProforma == id_proforma
join p in db.Proforma on ta.IDProforma equals p.ID
join pe in db.PortExpenses on ta.CodigoPE equals pe.CodigoPE
join v in db.Voucher on pe.IDVoucher equals v.No
select new CTarifaAplicada
{
CodigoFile = ta.CodigoFile,
CodigoPE = ta.CodigoPE,
Fecha = ta.Fecha,
Id = ta.Id,
IDProforma = ta.IDProforma,
ITBIS = ta.ITBIS,
Monto = ta.Monto,
DWT = p.DWT,
GRT=p.GRT,
LOA=p.LOA,
no_Voucher= v.No,
voucher=v.Description
}).ToList();
return pt;
我试图通过v.No进行分组,这样做。
Json(cta.get_TarifasAplicadas(id_Proforma).OrderBy(n => n.no_Voucher).GroupBy(n => n.no_Voucher)
这不会让我失望。在我的网格上,我是新手
答案 0 :(得分:0)
将您的方法定义为(返回Enumerable
而不是List
更明智):
public IEnumerable<CTarifaAplicada> get_TarifasAplicadas(int id_proforma)
{
var pt = (from ta in db.TarifaAplicada
where ta.IDProforma == id_proforma
join p in db.Proforma on ta.IDProforma equals p.ID
join pe in db.PortExpenses on ta.CodigoPE equals pe.CodigoPE
join v in db.Voucher on pe.IDVoucher equals v.No
select new CTarifaAplicada
{
CodigoFile = ta.CodigoFile,
CodigoPE = ta.CodigoPE,
Fecha = ta.Fecha,
Id = ta.Id,
IDProforma = ta.IDProforma,
ITBIS = ta.ITBIS,
Monto = ta.Monto,
DWT = p.DWT,
GRT=p.GRT,
LOA=p.LOA,
no_Voucher= v.No,
voucher=v.Description
});
return pt;
}
然后将数据分组并将其作为匿名类型投影为:
var groupedData = cta.get_TarifasAplicadas(id_Proforma)
.GroupBy(n => new {n.no_Voucher, n.voucher, n.DWT, n.GRT, n.LOA, n.Fecha})
.Select(g => new
{
g.Key.no_Voucher,
g.Key.voucher,
ITBIS = g.Sum(r => r.ITBIS),
MONTO = g.Sum(r => r.Monto),
g.Key.DWT,
g.Key.GRT,
g.Key.LOA,
g.Key.Fecha
});
现在,如果您的lib允许匿名类型序列化,则可以使用groupedData
序列化为JSON
。否则,您必须根据投影类型定义类型并使用它。