根据R中出现的次数对字符串数组进行排序

Question

输入：

Array = {"one", "two", "three", "three", "three","two"}

输出应为：

NewArray = {"three", "two", "one"}

什么是最简单和最好的在R中执行它的方式。我知道可以通过考虑哈希包甚至env来完成它。 不到5行代码？

Answer 1

也许来自`plyr'的count()：

require(plyr)
counts<-count(c("one", "two", "three", "three", "three","two"))
NewArray<-array(counts[order(-counts$freq),1])