Question

我有一个字符串如下：

set str = "HELLO SO COMMUNITY| CAN YOU HELP ME"
foreach word ($str)
    echo $word
end

目前，这打印HELLO然后是SO然后是COMMUNITY等等。我希望打印的分隔符为| 。所以输出应该是HELLO SO COMMUNITY然后你可以帮助我。有谁知道怎么做。

Answer 1

set str = "HELLO SO COMMUNITY| CAN YOU HELP ME"

set delimiter = '|'
set special_char = '_' # A character you know doesn't appear in your strings

set words = `echo $str | sed "s/ /$special_char/g" | sed "s/$delimiter/ /g"`
# words now contains "HELLO_SO_COMMUNITY _CAN_YOU_HELP_ME"

foreach word ($words)
    echo $word | sed "s/$special_char/ /g"
end

将special_char替换为您知道字符串中未出现的字符。小心任何特殊字符。我会避免使用*，?，$，\以及可能由cshell解释的其他令牌。 cshell的规则＃1是总是以错误的方式解释它们......：P

在csh中更改foreach的分隔符

1 个答案: