我正在使用YOURLS创建自己的网址缩短器。以下是对api进行POST后得到的输出。
我的问题是我似乎无法获得shorturl
参数。
{"url":
{"keyword":"ODuQT",
"url":"http:\/\/apple.com.sg",
"title":"Apple (Singapore)",
"date":"2013-12-02 16:38:51",
"ip":"219.74.124.134"
},
"status":"success",
"message":"http:\/\/apple.com.sg added to database",
"title":"Apple (Singapore)",
"shorturl":"http:\/\/qez4.me\/ODuQT",
"statusCode":200
}
我的代码在这里: -
function shortenURL($inputUrl) {
$url = 'http://qez4.me/s/yourls-api.php';
$fields = array('signature' => SHORTURL_SIGNATURE,
'action' => 'shorturl',
'url' => urlencode($inputUrl),
'format' => 'json');
//url-ify the data for the POST
foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
rtrim($fields_string,'&');
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_POST,count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);
//execute post
$result = curl_exec($ch);
$json = json_decode($result, true);
echo $json["shorturl"];
}
我也尝试过使用$json->shorturl
,但所有这些都是输出上面显示的json字符串。
答案 0 :(得分:0)
您的代码缺少cURL中的“返回转移”选项
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); //this line