Question

我从json dictionory获取字符串，但结果字符串在括号中，我必须得到没有backets的字符串

代码是

jsonDictionary  = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableContainers error:&error];        
NSDictionary *dictResult = [jsonDictionary objectForKey:@"result"];
NSDictionary *dictPronunciations = [dictResult valueForKey:@"pronunciations"];
NSDictionary *dictAudio = [dictPronunciations valueForKey:@"audio"];
NSString *strMp3Path = [dictAudio valueForKey:@"url"];
NSLog(@"str mp3 path %@",strMp3Path);

，结果是

(
    (
        "/v2/dictionaries/assets/ldoce/gb_pron/abate0205.mp3"
    )
)

我想将/v2/dictionaries/assets/ldoce/gb_pron/abate0205.mp3作为不带括号的字符串。请帮忙......

Answer 1

您要记录的对象不是NSString实例。它是数组中数组中的字符串。

尝试：

NSLog(@"str mp3 path %@",strMp3Path[0][0]);

如果按需打印，则对象dictAudio保持，键url是一个数组，带有数组。你应该把它固定在字典中。

Answer 2

尝试使用以下代码：

NSMutableArray *myArray = [dictAudio valueForKey:@"url"];
NSString *myStr = [[myArray objectAtIndex:0] objectAtIndex:0];
NSLog(@"%@", myStr);

Answer 3

使用此代码。如果您的值是json的倍数，则可以逐个添加值而不使用大括号：

NSMutableArray *dictPronunciations = [dictResult valueForKey:@"pronunciations"];

NSMutableArray *arrayPronunciations = [[NSMutableArray alloc] init];

for (int i = 0; i< [dictPronunciations count]; i++)
                 {
                     NSString *string = [dictPronunciations objectAtIndex:i];

                     NSLog(@"String = %@",string);

                     [arrayPronunciations addObject:string];
                 }

NSLog(@"Array Pronounciations = %@",arrayPronunciations);

如何获取字符串删除参数

3 个答案: