Question

我遇到了以下错误，错误指向的第158行如下所示。任何人都可以帮助解决问题以及如何解决问题？

def getGerritInfo(num):
    user = pwd.getpwuid(os.getuid())[0]
    gerritCmd = ("ssh -p 29418 review-android.quicinc.com gerrit query --format=JSON --dependencies ").split(' ')
    xargs = ['change:'+num]
    gerritPipe = Popen(gerritCmd+xargs, stdout=PIPE, stderr=PIPE) --> line 158
    (output, error) = gerritPipe.communicate()
    if error != "":
        print error
        raise IOError, "gerrit command %s failed" % (gerritCmd)
    d = json.loads(output.split('\n')[0])
    if len(d) == 3:
        return {}
    return d

错误： -

  File "find_dependencies.py", line 437, in <module>
    main()
  File "find_dependencies.py", line 211, in main
    (dep_gerrit,depgerrit_status,depgerrit_error)=findinternaldep(internal_dep,num)
  File "find_dependencies.py", line 100, in findinternaldep
    gerrit = getGerritInfo(change)
  File "find_dependencies.py", line 158, in getGerritInfo
    gerritPipe = Popen(gerritCmd+xargs, stdout=PIPE, stderr=PIPE)
  File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
    errread, errwrite)
  File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
    raise child_exception
TypeError: execv() arg 2 must contain only strings

Answer 1

尝试：

xargs = ['change:%s' % str(num)]

这将确保所有部分都是字符串。

在您的错误处理程序中，我个人也会设置d = {}而不是return {}，以确保您只有一个return。

TypeError：execv（）arg 2必须只包含字符串

1 个答案: