Question

{
    "204": {
        "host": "https:\/\/abc.com\/production-source\/ChangSha\/2013\/12\/02\/0\/0\/A\/Content\/",
        "timestamp": 1385909880,
        "cover": ["17\/Pg017.png",
        "18\/Pg018.png",
        "1\/Pg001.png",
        "2\/Pg002.png"],
        "year": "2013",
        "month": "12",
        "day": "02",
        "issue": "2013-12-02",
        "id": "204"
    },
    "203": {
        "host": "https:\/\/abc.com\/production-source\/ChangSha\/2013\/12\/01\/0\/0\/A\/Content\/",
        "timestamp": 1385806902,
        "cover": ["1\/Pg001.png",
        "2\/Pg002.png",
        "3\/Pg003.png",
        "4\/Pg004.png"],
        "year": "2013",
        "month": "12",
        "day": "01",
        "issue": "2013-12-01",
        "id": "203"
    },
    "202": {
        "host": "https:\/\/abc.com\/production-source\/ChangSha\/2013\/11\/30\/0\/0\/A\/Content\/",
        "timestamp": 1385720451,
        "cover": ["1\/Pg001.png",
        "2\/Pg002.png",
        "3\/Pg003.png",
        "4\/Pg004.png"],
        "year": "2013",
        "month": "11",
        "day": "30",
        "issue": "2013-11-30",
        "id": "202"
    }
}

以上示例json数组，如何获得204,203和202？感谢

我试过了：

JSONArray issueArray = new JSONArray(jsonContent);

for (int j = 0; j < issueArray.length(); j++) {
    JSONObject issue = issueArray.getJSONObject(j);
    String _pubKey = issue.getString(0);
}

Answer 1

以上示例json数组，如何获取204,203和202？

不，当前字符串是JSONObject而不是JSONArray。如果内部JSONObject键动态为：

，则应使用JSONObject. keys ()使用Iterator

JSONObject issueObj = new JSONObject(jsonContent);
Iterator iterator = issueObj.keys();
   while(iterator.hasNext()){
    String key = (String)iterator.next();
    JSONObject issue = issueObj.getJSONObject(key);

    //  get id from  issue
        String _pubKey = issue.optString("id");
    }

Answer 2

K先生给出的答案也是对的，但您也可以使用 jsonObject names（）方法。请找到示例代码

for(int i = 0; i<jsonobject.length(); i++){
    Log.e(TAG, "Key = " + jsonobject.names().getString(i) + " value = " + jsonobject.get(jsonobject.names().getString(i)));
}

我希望dis会帮助你

Answer 3

使用此方法动态迭代json

private void parseJson(JSONObject data) {

        if (data != null) {
            Iterator<String> it = data.keys();
            while (it.hasNext()) {
                String key = it.next();

                try {
                    if (data.get(key) instanceof JSONArray) {
                        JSONArray arry = data.getJSONArray(key);
                        int size = arry.length();
                        for (int i = 0; i < size; i++) {
                            parseJson(arry.getJSONObject(i));
                        }
                    } else if (data.get(key) instanceof JSONObject) {
                        parseJson(data.getJSONObject(key));
                    } else {
                        System.out.println("" + key + " : " + data.optString(key));
                    }
                } catch (Throwable e) {
                    System.out.println("" + key + " : " + data.optString(key));
                    e.printStackTrace();

                }
            }
        }
    }

Answer 4

在这里，您尝试获取JSONArray，但在json响应中，它是JSONObject。

使用以下代码。

JSONObject issueObject = new JSONObject(jsonContent);
String _pubKey = issueObject.getString(0);

在android中获取json数组键

4 个答案: