Question

我一直在寻找一个脚本来创建一个以圆周运动移动很长一段时间的光标文本轨迹。五年前我觉得这些东西到处都是俗气的博客网站。

我能找到的唯一代码由Tim Tilton撰写，发现变化 here和here 并在其他几个网站上重复。

这段代码似乎有点沉重，因为它分离并给出消息的每个字符它自己的div然后使用方程放置并移动光标周围的div。

还有另一种方法可以创建这样的功能吗？

这里有一些沉重的代码：

if (!window.addEventListener && !window.attachEvent || !document.createElement) return;

msg = msg.split('');
var n = msg.length - 1, a = Math.round(size * diameter * 0.208333), currStep = 20,
ymouse = a * circleY + 20, xmouse = a * circleX + 20, y = [], x = [], Y = [], X = [],
o = document.createElement('div'), oi = document.createElement('div'),
b = document.compatMode && document.compatMode != "BackCompat"? document.documentElement : document.body,

mouse = function(e){
 e = e || window.event;
 ymouse = !isNaN(e.pageY)? e.pageY : e.clientY; // y-position
 xmouse = !isNaN(e.pageX)? e.pageX : e.clientX; // x-position
},

makecircle = function(){ // rotation/positioning
 if(init.nopy){
  o.style.top = (b || document.body).scrollTop + 'px';
  o.style.left = (b || document.body).scrollLeft + 'px';
 };
 currStep -= rotation;
 for (var d, i = n; i > -1; --i){ // makes the circle
  d = document.getElementById('iemsg' + i).style;
  d.top = Math.round(y[i] + a * Math.sin((currStep + i) / letter_spacing) * circleY - 15) + 'px';
  d.left = Math.round(x[i] + a * Math.cos((currStep + i) / letter_spacing) * circleX) + 'px';
 };
},

drag = function(){ // makes the resistance
 y[0] = Y[0] += (ymouse - Y[0]) * speed;
 x[0] = X[0] += (xmouse - 20 - X[0]) * speed;
 for (var i = n; i > 0; --i){
  y[i] = Y[i] += (y[i-1] - Y[i]) * speed;
  x[i] = X[i] += (x[i-1] - X[i]) * speed;
 };
 makecircle();
},

init = function(){ // appends message divs, & sets initial values for positioning arrays
 if(!isNaN(window.pageYOffset)){
  ymouse += window.pageYOffset;
  xmouse += window.pageXOffset;
 } else init.nopy = true;
 for (var d, i = n; i > -1; --i){
  d = document.createElement('div'); d.id = 'iemsg' + i;
  d.style.height = d.style.width = a + 'px';
  d.appendChild(document.createTextNode(msg[i]));
  oi.appendChild(d); y[i] = x[i] = Y[i] = X[i] = 0;
 };
 o.appendChild(oi); document.body.appendChild(o);
 setInterval(drag, 25);
},

ascroll = function(){
 ymouse += window.pageYOffset;
 xmouse += window.pageXOffset;
 window.removeEventListener('scroll', ascroll, false);
};

o.id = 'outerCircleText'; o.style.fontSize = size + 'px';

if (window.addEventListener){
 window.addEventListener('load', init, false);
 document.addEventListener('mouseover', mouse, false);
 document.addEventListener('mousemove', mouse, false);
  if (/Apple/.test(navigator.vendor))
   window.addEventListener('scroll', ascroll, false);
}
else if (window.attachEvent){
 window.attachEvent('onload', init);
 document.attachEvent('onmousemove', mouse);
};

在光标周围盘旋文本踪迹

0 个答案: