到目前为止工作
SELECT subject_en_name FROM subjects
INNER JOIN teachers_subjects
ON subjects.subject_id = teachers_subjects.subject_id
WHERE teachers_subjects.teacher_user_id = 6
这让我的主题名称很好。但是,我想不选择teachers_subjects.teacher_user_id,而是选择users_teachers.user_id。
我尝试过类似的事情:
SELECT subject_en_name FROM subjects
INNER JOIN teachers_subjects
ON subjects.subject_id = teachers_subjects.subject_id
INNER JOIN users_teachers
ON teachers_subjects.teacher_user_id = users_teachers.user_id
WHERE users_teachers.user_id = 98
但是当我这样做时,它不会返回任何结果,它应返回2行
由于