使用Disruptor环形缓冲区,我每秒只能实现600万次操作。我想知道我哪里出错了。我的事件处理程序只是一个计数器。这是单生产者和单一消费者。有人可以告诉我,如果我对语义本身有误。该程序创建一个生成器线程,该线程将添加到缓冲区。并创建一个事件处理程序来处理发布事件。每次发布事件时,事件处理程序都会增加一个易失性计数器。
public class MainClass{
public static class globalVariables
{
static int NUMBER_OF_ITERATIONS = 33554432; // 2 power 25
static int NUMBER_OF_THREADS;
static int RING_SIZE = NUMBER_OF_ITERATIONS;
static int WRITE_CODE = 1;
static volatile int keep_going = 1;
};
public void start_execution()
{
int remainder = globalVariables.NUMBER_OF_ITERATIONS % globalVariables.NUMBER_OF_THREADS;
int iterations_per_thread = ( globalVariables.NUMBER_OF_ITERATIONS - remainder ) / globalVariables.NUMBER_OF_THREADS ;
/* New Shared Object */
final sharedObject newSharedObject = new sharedObject();
ExecutorService exec = Executors.newFixedThreadPool(1);
Disruptor<valueEvent> disruptor = new Disruptor<valueEvent>( valueEvent.EVENT_FACTORY, globalVariables.RING_SIZE, exec );
/* Creating event handler whenever an item is published in the queue */
final EventHandler<valueEvent> handler = new EventHandler<valueEvent>()
{
public void onEvent(final valueEvent event, final long sequence,
final boolean endOfBatch) throws Exception
{
newSharedObject.shared_variable++; // increment the shared variable
}
};
/* Use the above handler to handler events */
disruptor.handleEventsWith(handler);
/* start Disruptor */
final RingBuffer<valueEvent> ringBuffer = disruptor.start();
final long[] runtime = new long [globalVariables.NUMBER_OF_THREADS];
/* Code the producer thread */
final class ProducerThread extends Thread {
int i;
public ProducerThread( int i )
{
this.i = i;
}
public void run()
{
long idle_counter = 0;
long count;
System.out.println("In thread "+i );
long startTime = System.nanoTime();
//while( globalVariables.keep_going == 1 )
for( int counter=0; counter<globalVariables.NUMBER_OF_ITERATIONS; counter++ )
{
// Publishers claim events in sequence
long sequence = ringBuffer.next();
valueEvent event = ringBuffer.get(sequence);
event.setValue(globalVariables.WRITE_CODE);
// make the event available to EventProcessors
ringBuffer.publish(sequence);
}
long stopTime = System.nanoTime();
runtime[i] = (stopTime - startTime)/1000;
}
};
/* ------------------------------------------------------------------------------- */
//final class AlarmHandler extends TimerTask {
/*** Implements TimerTask's abstract run method. */
// @Override public void run(){
// globalVariables.keep_going = 0;
// }
// };
/* ------------------------------------------------------------------------------- */
/* Creating Producer threads */
ProducerThread[] threads = new ProducerThread[globalVariables.NUMBER_OF_THREADS];
for (int i = 0; i < globalVariables.NUMBER_OF_THREADS; i++) {
threads[i] = new ProducerThread( i );
threads[i].start();
}
// Waiting for the threads to finish
for (int i = 0; i < globalVariables.NUMBER_OF_THREADS; i++) {
try
{
threads[i].join();
} catch ( InterruptedException e ) { System.out.println("hi exception :)"); }
}
/* shutdown */
disruptor.shutdown();
exec.shutdown();
/* Printing Statistics */
System.out.println( "Shared Variable: " + newSharedObject.shared_variable );
for ( int i=0; i<globalVariables.NUMBER_OF_THREADS; i++ )
{
System.out.println("Runtime="+ runtime[i] + "; Operations per second = " + (globalVariables.NUMBER_OF_ITERATIONS / runtime[i] )*1000000 +"ops/sec" );
}
}
public static void main( String args[] )
{
globalVariables.NUMBER_OF_THREADS = Integer.parseInt( args[0] );
System.out.println( "Number of Threads = "+ globalVariables.NUMBER_OF_THREADS );
MainClass mainObj = new MainClass();
mainObj.start_execution();
System.exit(0);
}
};
这是程序的输出
共享变量:33554432; 运行时间= 5094139微秒;每秒操作数= 6000000
非常感谢任何帮助。
答案 0 :(得分:0)
由于您在单个线程中运行事件处理程序,并且不共享该状态,因此通过使事件处理程序在非易失性字段上工作,您应该获得明显更好的性能(但仍然是正确的函数)。破坏程序确保您的处理程序一次只处理一个事件,因此您不必担心丢失增量。
如果系统中的另一个组件依赖于以特定顺序出现的此值(例如:它是一个控制值),那么您应该考虑使用类似AtomicInteger和lazySet [1]的东西。
[1] http://psy-lob-saw.blogspot.com.au/2012/12/atomiclazyset-is-performance-win-for.html