Question

无法创建最后一个表:(在我看来答案应该很简单，但遗憾的是找不到它。这是代码：

CREATE TABLE Topics ( topicId INT NOT NULL AUTO_INCREMENT, 
        topicName VARCHAR(50) NOT NULL,
        submdate DATE NOT NULL,
        accdate DATE NOT NULL, 
        comm VARCHAR(100), 
        status varchar(1) CHECK (status>0 and status<4),
        PRIMARY KEY (topicId) );


CREATE TABLE Student ( studentId INT NOT NULL AUTO_INCREMENT,
        studentname VARCHAR(50) NOT NULL,
        PRIMARY KEY (studentId) );  


CREATE TABLE TopicStudent ( topicId INT NOT NULL,
            studentId INT NOT NULL,
            PRIMARY KEY (topicId, studentId),
            CONSTRAINT Constr_TopicStudent_Student_fk
                FOREIGN KEY Student_fk (studentId) REFERENCES Student (studentId)
                ON DELETE CASCADE ON UPDATE CASCADE,
            CONSTRAINT Constr_TopicStudent_Topic_fk
                FOREIGN KEY Topic_fk (topicId) REFERENCES Topic (topicId)
                ON DELETE CASCADE ON UPDATE CASCADE
            );

错误1064（42000）：您的SQL语法有错误;查看与您的MySQL服务器版本对应的手册，以便在第1行的'Const r_TopicStudent_Student_fk FOREIGN KEY Student_fk（studentId）REFERENCES Stu'附近使用正确的语法

Answer 1

Const r_TopicStudent？ “Const”和“r_TopicStudent”之间是否有空格？

MySQL多对多的关系

1 个答案: