Question

我有一个简单的问题。

目前，我的网站www.rune-shadows.com/serverintegration.php上有一个名为“serverintegration.php”的PHP文件。

我有一个java加载并运行文件中的PHP代码。

问题是，它读取html（源代码）而不是运行PHP。如何让它读取并运行PHP？这是我目前的代码：

错误：

[12/1/13 10:00 AM]: Web server not responding for query: <br />

ForumIntegration.java

package com.rs2.util;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import com.rs2.model.players.Player;

public class ForumIntegration {

private static final int CRYPTION_ID = 4469139;
private static final String WEBSITE_DOMAIN = "http://www.rune-shadows.com";
private static String OUTPUT_DATA;

public static int ProcessUser(Player player) {
    try {
        String URL = WEBSITE_DOMAIN + "/serverintegration.php?crypt="
                + CRYPTION_ID + "&name="
                + player.getUsername().toLowerCase().replace(" ",  "_")
                + "&pass=" + player.getPassword();
        HttpURLConnection CONNECTION_HANDLE = (HttpURLConnection) new URL(
                URL).openConnection();
        BufferedReader OUTPUT_HANDLE = new BufferedReader(
                new  InputStreamReader(CONNECTION_HANDLE.getInputStream()));

        OUTPUT_DATA = OUTPUT_HANDLE.readLine().trim();
        try {
            // Parse returned internet data.
            int RETURN_CODE = Integer.parseInt(OUTPUT_DATA);
            switch (RETURN_CODE) {

            case -1:
                System.out.println("Wrong CRYPTION_ID.");
                return 10;

            case 1:// Invalid Password.
                return 3;

            case 2:
                int memberGroupId = RETURN_CODE - 2;
                return 2;

            case 0:// no member exists for this username

                return 12;// say they must register on forum

            default:

                return 12;// say they must register on forum

            }
        } catch (Exception e) {

            System.out.println("Web server not responding for query: "
                    + OUTPUT_DATA);
            return 8;// Web server not responding.

        }
    } catch (Exception e2) {
    }

    System.out.println("Web server not responding for query: "
            + OUTPUT_DATA);
    return 11;// website offline
}
}

ServerIntegration.php

<?php
$SQL_HOST = "";
$SQL_USERNAME = "";
$SQL_PASSWORD = "";
$DATABASE_NAME = "";
$CRYPTION_ID = 4469139;

//Check if number is correct.
if($_GET['crypt'] != $CRYPTION_ID) {
echo '-1';
exit;
}

//Declare variables input.
$NAME_INPUT = str_replace("_"," ",$_GET['name']);
$PASS_INPUT = $_GET['pass'];

//Try to connect with specified SQL Server.
if(!@mysql_connect($SQL_HOST, $SQL_USERNAME, $SQL_PASSWORD))
die("Error connecting to SQL Server - " . mysql_error());   

//Select the specified SQL database.
if(!@mysql_select_db($DATABASE_NAME))
die("Error selecting SQL Database - " . mysql_error());

//Query Selected SQL Database.
$SQL_QUERY = mysql_query("SELECT * FROM users WHERE ".$CALL_FROM." =  '".$NAME_INPUT."'");

//Compare login information.
if ($SQL_ROW = mysql_fetch_array($SQL_QUERY)){

if(strcmp($SQL_ROW["username"], $NAME_INPUT) != 0) {//Compare input username to SQL database.

    echo '0'; //Query denied(No user found).

} else {
    $DATABASE_PASSWORD = md5(md5($PASS_INPUT).$SQL_ROW["salt"]);//Generate     correct Password to compare with SQL Database.

    if(strcmp($DATABASE_PASSWORD, $SQL_ROW["password"]) == 0) { //Determine if     password is correct.

        echo '2'; //Successful login.

    } else { 

        echo '1'; //The input Password is incorrect.
    }
}
} else {
echo '0'; //Query denied(Database declined query).
}
?>

Answer 1

我收集的是您希望客户端在本地呈现PHP页面吗？

PHP代码由具有PHP处理器模块的Web服务器解释，因此除非每个客户端运行一些奇怪的混合Web服务器，否则您的工作将无法正常工作。

Answer 2

问题是你在后端遇到mysql错误。要查看粗略的代码，请添加以下代码 String line = null; while（（line = OUTPUT_HANDLE.readLine（））！= null）{ 的System.out.println（线）; }

而不是OUTPUT_DATA = OUTPUT_HANDLE.readLine().trim();以及我通过使用空参数点击URL看到的是

<br />
<b>Warning</b>:  mysql_fetch_array() expects parameter 1 to be resource, boolean given in <b>/home/content/23/9717823/html/serverintegration.php</b> on line <b>36</b><br />
0
Web server not responding for query: null

希望这有帮助。

使用Java读取外部PHP文件

2 个答案: