Question

在Creating a timer with passing a PHP variable的扩展中，在将脚本添加到剩余的代码部分之后，我有一些跟进问题。似乎没有通过再次在那里发布来引起对问题的关注？希望对此事做一些澄清。

<html><head>
<?php $variable = "2013-12-01 17:00:00";?>
<script type="text/javascript">

function counter() {
    var variable = <?php echo (json_encode($variable)) ?>;
    var t = variable.split(/[- :]/);
    var gametime = new Date(t[0], t[1]-1, t[2], t[3], t[4], t[5]);
    var now = new Date();
    var timeDiff = gametime.getTime() - now.getTime();
    var timer = setTimeout('counter()');
    if (timeDiff <= 0) {
            clearTimeout(timer);
        }
    var seconds = Math.floor(timeDiff / 1000);
    var minutes = Math.floor(seconds / 60);
    var hours = Math.floor(minutes / 60);
    var days = Math.floor(hours / 24);
    hours %= 24;
        minutes %= 60;
        seconds %= 60;
    document.getElementById("days").innerHTML = days;
    document.getElementById("hours").innerHTML = hours;
    document.getElementById("mins").innerHTML = minutes;
    document.getElementById("sec").innerHTML = seconds;
}
</script>
</head>
<body> 
 <?php include 'header.html'; ?>   
        <div id="content">
            <?php 
            $vip = "= '0'";
            getOpenPicks($vip);
            if (empty($rowset)) {
                print "There are no open bets at the moment";
            } else {
                foreach ($rowset as $row) {?>
                    <form>
                    Time remaining: <label id=days></label>:<label id=hours></label>:<label id=mins></label>:<label id=sec></label><br>
                    <script type="text/javascript">counter();</script>
                    Match: <label for="home"><?php echo $row[1]?></label>
                    - <label for="away"><?php echo $row[2]?></label><br>
                    Bet: <label for="pick"><?php echo $row[3]?> </label><br>
                    Odds: <label for="pick"><?php echo $row[4]?></label><br>
                    Units: <label for="units"><?php echo $row[5]?></label><br>
                    </form><br>
<?php           } 
                }?>     
        </div>

我对javascript很新，但是不可能在foreach循环中多次调用脚本吗？我问，因为我知道我的SQL查询中有几个不同的行，但计时器只显示在第一个？或者这可能是第一次没有传递的php变量的问题？

在foreach循环中调用javascript

0 个答案: