Question

这是用于上传的PHP代码：

$upload = "uploads/";
$upload = $upload . basename($_FILES['bgimage']['name']);

if (move_uploaded_file($_FILES['bgimage']['tmp_name'], $upload)) {

    echo "The file has been uploaded successfully.";

} else { echo "Error"; }

当我测试脚本时，它会显示“文件已成功上传”。但是当我检查FTP服务器时，它确实没有......

此外，如果您需要知道，这是HTML代码：

表格标签：

<form name="profilestyle" action="account.php?action=profiletheme" method="post" enctype="multipart/form-data">

输入标记：

<input type="file" name="bgimage" />

额外信息：是的，我记得CHM上传目录

Answer 1

奇怪的是，就我所见，代码看起来很好。

您是否可以使用file_exists()检查文件是否存在，但您的FTP用户可能无法看到？

if (move_uploaded_file($_FILES['bgimage']['tmp_name'], $upload)) {

echo "The file '$upload' has been uploaded successfully.";
if (file_exists($upload)) echo "And it exists! It is ".filesize($upload)." bytes big.";
 else echo "But it doesn't exist.";

} else { echo "Error"; }

Answer 2

您还需要检查$_FILES['bgimage']['error']以确保它等于UPLOAD_ERR_OK并且不是错误代码。

Answer 3

请尝试以下测试代码

$upload = "uploads/";
$upload = $upload . basename($_FILES['bgimage']['name']);

sprintf('<pre>Debug: moving file from %s to %s</pre>',
  $_FILES['bgimage']['tmp_name'],
  $upload
);
if (move_uploaded_file($_FILES['bgimage']['tmp_name'], $upload)) {
  echo "The file has been uploaded successfully.";
  sprintf('<pre>Debug: realpath=%s, filesize=%d</pre>',
    realpath($upload),
    filesize($upload)
  );
}
else {
  echo "Error";
}

和esp。密切关注realpath = xyz输出。

上传文件不起作用，这段代码有什么问题？

3 个答案: