Question

我在同一个项目中完成了（几乎）完全相同的数组返回，并且编译了一个类（PlayerArray）但是由于某些原因我尝试在my（{{1）中返回一个数组它给了我错误“Planet”，但我不明白为什么会这样，我的意思是该方法返回一个数组，它确实返回一个数组？如果有人可以解释这些差异以及为什么一个人工作而另一个人抱怨“不兼容的类型”那么那就太棒了。谢谢！这是我的一些代码。

这是我的发射器。

Incompatible Types

播放器阵列波纹管工作..

public class Launcher
{
private static Planet myTest;
private static PlanetInfo myPlanetInfo;
private static PlanetInfo[] planetArray;
private static Player[] arr; //NEED THIS FOR arr = myArray.getPlayerArray(); to work..
public static void main(String[] args)
{
    Planet myPlanetArray = new Planet();
    PlayerArray myArray = new PlayerArray();
    myPlanetArray.getPlanetArray();
    myArray.getPlayerArray();
    planetArray = myPlanetArray.returnCost();/////////////////////THIS IS THE BROKEN LINE
    arr = myArray.getPlayerArray(); //holy moses this worked...
    System.out.println("player 1's ID: " + arr[0].viewID());
    System.out.println("player 1's balance: " + arr[0].viewBalance());
    arr[0].playerGo();
}
}

这里是不会编译的类...

public class PlayerArray
{
Scanner scan = new Scanner(System.in);
private int numbHuman;
private Player[] arr;
private String[] userName;
private int[] userID;
private int startingMoney;
private int startingPosition;
private int b;
public PlayerArray()
{
    Scanner scan = new Scanner(System.in);
    System.out.println("How many players wish to play? Values of 2 through 8 accepted.");
    numbHuman = scan.nextInt();
    System.out.println(numbHuman + " players selected.");
    while (numbHuman < 2 || numbHuman > 8)
    {
        System.out.println("Invalid entry, try again.");
        numbHuman = scan.nextInt();
    }       
    arr = new Player[numbHuman];
    userName = new String[numbHuman];
    userID = new int[numbHuman];
    startingMoney = 1500;
    startingPosition = 0;
    b=0;
    for(int i = 0; i < arr.length; i++)
    {

        userID[i] = b;
        System.out.println("Player " + (i + 1) + ", Please enter your first name:");
        userName[i] = scan.next();
        arr[i] = new Player(userName[i],startingMoney,userID[i],startingPosition);
        b++;
    }
}

public int viewNumbHuman()
{
    return numbHuman;
}

public Player[] getPlayerArray()
{   
    return arr; //WORKS HERE...
}
}

Answer 1

字段planetArray以

声明

private static Planet[] planetArray;

并且您尝试在带签名

的方法中返回它

public PlanetInfo[] getPlanetArray()

你的方法

public void Planets()

有一个你期望的类型的局部变量，但这与getPlanetArray方法无关。

Planets方法也是一个令人困惑的方法，因为看起来你可能打算创建一个构造函数，但给它一个错误的签名作为构造函数并在其中实例化Planets对象

Java~返回数组时不兼容的类型？

1 个答案: