Question

在下面的代码中第一个方法（generateRandomNumber）生成1到10之间的随机数。然后第二个方法（guessRandomNumber）允许用户猜测数字。我遇到的问题是，当用户猜错号码时，它会生成另一个随机数而不是初始数。因此，即使输入每个可能的数字，用户也可以猜测并且永远不会正确。任何人都可以建议我如何改变这一点。

第一种方法（生成数字）：

public static int generateRandomNumber() {

    Random random = new Random();
    // Declaring int for random number and defaulting to 0
    int randomNumber = 0;
    // Assigning randomNumber between 1 and 10
    randomNumber = random.nextInt(10);
    randomNumber++;

    return randomNumber;

}// end of generateRandomNumber

第二种方法（猜数字）：

public static void guessRandomNumber() {

        // declare var for user guess and default to zero
        int userGuess = 0;
        boolean validNumber=false;
        boolean correctGuess=false;
do{

    do{
    try{
        validNumber=true;
        // Get user guess (between 1 and 10)
        System.out.println("Please enter a number between 1 and 10...");
        userGuess = scanner.nextInt();
    }catch (Exception ex){
        System.out.println("Sorry invalid entry...");
        //Flush scanner
        scanner.next();
        validNumber=false;
    }
    }while (!validNumber);
        if (userGuess == generateRandomNumber()) {

            System.out.println("Guess correct, well done!");
            correctGuess=true;

        } else {

            System.out.println("Sorry guess Incorrect please try again!");
            correctGuess=false;
        }
}while (!correctGuess);
    }// end ofGuessRandomNumber

尝试：

public static void guessRandomNumber() {

        // declare var for user guess and default to zero
        int userGuess = 0;
        boolean validNumber=false;
        boolean correctGuess=false;
        int secretNumber=generateRandomNumber();
do{

    do{
    try{
        validNumber=true;
        // Get user guess (between 1 and 10)
        System.out.println("Please enter a number between 1 and 10...");
        userGuess = scanner.nextInt();
    }catch (Exception ex){
        System.out.println("Sorry invalid entry...");
        //Flush scanner
        scanner.next();
        validNumber=false;
    }
    }while (!validNumber);
        if (userGuess == secretNumber) {

            System.out.println("Guess correct, well done!");
            correctGuess=true;

        } else {

            System.out.println("Sorry guess Incorrect please try again!");
            correctGuess=false;
        }
}while (!correctGuess);
    }// end ofGuessRandomNumber

Answer 1

您需要先在用户猜测之前生成随机数，然后将其存储在变量中。然后，而不是在行

中调用generateRandomNumber()

if (userGuess == generateRandomNumber())

您需要将其与该变量进行比较。

Answer 2

您应该在第一次执行循环之前生成随机数。将其保存在名为correctNumber的变量中，然后测试userGuess == correctNumber。

保持方法之间的随机数相同

2 个答案: