Question

我对这张表格有一个奇怪的问题。我昨天晚上做了它，它工作正常，发送所有的电子邮件应该。但是，我今天运行它并不会简单地工作。我总是收到错误消息。有线索吗？谢谢。

 <?php
$name     =   $_POST['name']; 
$email    =   $_POST['email']; 
$subject  =   $_POST['subject']; 
$message  =   $_POST['message']; 
$depart = $_POST['departamento']; 

$headers  = "From: $email\r\n";
$headers .= "Reply-To: $email\r\n";



   $corpo = "Nova Mensagem\n";
   $corpo .= "De: " . $name . "\n"; 
   $corpo .= "Email: " . $email . "\n";
   $corpo.=" Para o departamento " . $depart. "\n";
   $corpo .= "Mensagem: " . $message . "\n";
    if ($depart = administrativo)
     {
      $email_to = ''; 
       }
       elseif ($depart = financeiro)
       {
       $email_to = ''; 
        }
   elseif ($depart = Suporte)
         {
    $email_to = ''; 
      }
     else
      {
     $email_to = ''; 
    }


$status = mail($email_to, $subject, $corpo, $headers); 

if($status) {
    echo "<script> window.location.href = ''; </script>";
}
else {
    echo "<script> window.location.href = ''; </script>";
}
?>

Answer 1

而不是 = 使用 == 进行比较

例如

- 而不是：

if( $depart = administrativo)

使用

if( $depart == "administrativo" )

Answer 2

您应该将字符串括在quotes中。此外，==（比较不同类型的对象）＆amp;＆amp; ===（比较相同类型的对象）用于比较，=用于分配。因此，请按如下所示更改代码（在if语句中）：

if ($depart == 'administrativo')
{
    $email_to = ''; 
}
elseif ($depart == 'financeiro')
{
    $email_to = ''; 
}
elseif ($depart == 'Suporte')
{
    $email_to = ''; 
}
else
{
    $email_to = ''; 
}

联系表格上的奇怪行为

2 个答案: