我在D3中有一个定向图,它显示了某些属性之间的某种关系。现在我已经为该应用程序添加了一个功能,我可以一次选择多个节点,所选节点值将进入控制台。现在我想将选定的值发送到Servlet,但是在值即将到来的形式中,我无法将它们分开并将它们发送到Servlet。这是我的代码....
<!DOCTYPE html>
<meta charset="utf-8">
<style>
.link {
fill: none;
stroke: #666;
stroke-width: 1.5px;
}
#licensing {
fill: green;
}
.link.licensing {
stroke: green;
}
.link.resolved {
stroke-dasharray: 0, 2 1;
}
circle {
fill: #ccc;
stroke: #333;
stroke-width: 1.5px;
}
text {
font: 10px sans-serif;
pointer-events: none;
text-shadow: 0 1px 0 #fff, 1px 0 0 #fff, 0 -1px 0 #fff, -1px 0 0 #fff;
}
.brush .extent {
fill-opacity: .1;
stroke: #fff;
shape-rendering: crispEdges;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
// http://blog.thomsonreuters.com/index.php/mobile-patent-suits-graphic-of-the-day/
/*Here licensing type is making the green arrow
*Here resolved type is making the solid arrow
*Here suit type is making the dotted arrow
*
*
**/
var links = [];
var nodes = {};
// Compute the distinct nodes from the links.
var width = 960, height = 500;
var svg = d3.select("body").append("svg").attr("width", width).attr(
"height", height);
// Per-type markers, as they don't inherit styles.
svg.append("defs").selectAll("marker").data(
[ "suit", "licensing", "resolved" ]).enter().append("marker")
.attr("id", function(d) {
return d;
}).attr("viewBox", "0 -5 10 10").attr("refX", 15).attr("refY",
-1.5).attr("markerWidth", 6).attr("markerHeight", 6)
.attr("orient", "auto").append("path").attr("d",
"M0,-5L10,0L0,5");
d3.json(
"directed.json",
function(error, directed) {
links=directed.links;
links.forEach(function(link) {
link.source = nodes[link.source]
|| (nodes[link.source] = {
name : link.source
});
link.target = nodes[link.target]
|| (nodes[link.target] = {
name : link.target
});
});
var force = d3.layout.force().nodes(
d3.values(nodes)).links(links).size(
[ width, height ]).linkDistance(60).charge(
-300).on("tick", tick).start();
var path = svg.append("g").selectAll("path").data(
force.links()).enter().append("path").attr(
"class", function(d) {
return "link " + d.type;
}).attr("marker-end", function(d) {
return "url(#" + d.type + ")";
});
var circle = svg.append("g").selectAll("circle")
.data(force.nodes()).enter().append(
"circle").attr("r", 6).call(
force.drag);
var text = svg.append("g").selectAll("text").data(
force.nodes()).enter().append("text").attr(
"x", 8).attr("y", ".31em").text(
function(d) {
return d.name;
});
//selection is happening
var selected = circle.filter(function(d) {
return d.name;
});
selected.each(function(d) {
// d contains the data for the node and this is the circle element
//console.log(d.name);
});
var circle = svg.append("g").selectAll("circle")
.data(force.nodes()).enter().append(
"circle").attr("r", 6).on("click",
clickfn).call(force.drag);
var clickfn = function(circle) {
alert(circle);
}
// Use elliptical arc path segments to doubly-encode directionality.
function tick() {
path.attr("d", linkArc);
circle.attr("transform", transform);
text.attr("transform", transform);
}
function linkArc(d) {
var dx = d.target.x - d.source.x, dy = d.target.y
- d.source.y, dr = Math.sqrt(dx * dx
+ dy * dy);
return "M" + d.source.x + "," + d.source.y
+ "A" + dr + "," + dr + " 0 0,1 "
+ d.target.x + "," + d.target.y;
}
function transform(d) {
return "translate(" + d.x + "," + d.y + ")";
}
var brush = svg.append("g")
.datum(function() { return {selected: false, previouslySelected: false}; })
.attr("class", "brush")
.call(d3.svg.brush()
.x(d3.scale.identity().domain([0, width]))
.y(d3.scale.identity().domain([0, height]))
.on("brushend", function(d) {
console.log(d3.selectAll("circle.selected"));
})
.on("brush", function() {
var extent = d3.event.target.extent();
circle.classed("selected", function(d) {
return d.selected = d.previouslySelected ^
(extent[0][0] <= d.x && d.x < extent[1][0]
&& extent[0][1] <= d.y && d.y < extent[1][1]);
});
}));
});
</script>
这是我正在加载图表的json
{
"links" : [ {
"source" : "Microsoft",
"target" : "Amazon",
"type" : "licensing"
}, {
"source" : "Microsoft",
"target" : "HTC",
"type" : "licensing"
}, {
"source" : "Samsung",
"target" : "Apple",
"type" : "suit"
}, {
"source" : "Motorola",
"target" : "Apple",
"type" : "suit"
}, {
"source": "Nokia",
"target": "Apple",
"type" : "resolved"
}, {
"source": "HTC",
"target": "Apple",
"type" : "suit"
}, {
"source" : "Kodak",
"target" : "Apple",
"type" : "suit"
}, {
"source": "Microsoft",
"target": "Barnes & Noble",
"type" :"suit"
}, {
"source": "Microsoft",
"target": "Foxconn",
"type" :"suit"
}, {
"source": "Apple",
"target": "HTC",
"type" :"suit"
}, {
"source" : "Microsoft",
"target" : "Inventec",
"type" : "suit"
}, {
"source" : "Samsung",
"target" : "Kodak",
"type" : "resolved"
}, {
"source" : "LG",
"target" : "Kodak",
"type" : "resolved"
}, {
"source": "RIM",
"target": "Kodak",
"type" :"suit"
}, {
"source" : "Sony",
"target" : "LG",
"type" : "suit"
}, {
"source" : "Kodak",
"target" : "LG",
"type" : "resolved"
}, {
"source" : "Apple",
"target" : "Nokia",
"type" : "resolved"
}, {
"source": "Qualcomm",
"target": "Nokia",
"type" :"resolved"
}, {
"source" : "Kodak",
"target" : "Samsung",
"type" : "resolved"
}, {
"source" : "Apple",
"target" : "Samsung",
"type" : "suit"
}, {
"source": "Kodak",
"target": "RIM",
"type" :"licensing"
}, {
"source": "Kodak",
"target": "Qualcomm",
"type" :"licensing"
} ]
}
现在,如果我一次选择多个节点,这些值将进入控制台,但是我不能将它们分开,也不能使用它们将它们发送到Servlet.Suppose,如上图所示我选择sony&amp; LG他们将来到控制台。但是这种格式
阵列1 0:数组[2] 0:圈 数据:对象 指数:11 名称:“LG”
并且索尼也会来,但是从这里我不能分开并使用它们有人请帮忙。