我正在尝试使用preg_match_all获取图像,但是无法在此处获取它是我的代码。我的问题,我有.img ext和一些.jpg的wome图像?w = 655& h = 357,我不需要.img但需要所有其他有效的图像吗?w = 655& h = 357 in last或者只是.jpg或.png
$post ='
<img width="1" height="1" src="http://pi.feedsportal.com/r/180265248066/u/49/f/648326/c/35070/s/34410e29/a2t.img" border="0"/></br>
<img width="1" height="1" src="http://9to5mac.files.wordpress.com/2013/11/screen-shot-2013-11-29-at-5-17-15-pm.png?w=655&h=357" border="0"/></br>
<img src="http://images.macrumors.com/article-new/2013/11/mlb.png" alt="MLB" title="mlb.png" width="175" height="175" class="alignright"/></br>
';
function catch_that_image($post) {
global $post, $posts;
$first_img = '';
ob_start();
ob_end_clean();
$output = preg_match_all("<img.+?src=[\"']([^\"]*\.(gif|jpg|jpeg|png).*)[\"'].+?>", $post, $matches);
$first_img = $matches [1] [0];
return $first_img;
}
echo catch_that_image($post);
输出
http://images.macrumors.com/article-new/2013/11/mlb.png" alt="MLB" title="mlb.png" width="175" height="175" class="alignright
我只需要url直到.png
由于
答案 0 :(得分:1)
不要使用正则表达式来解析HTML。请改用DOM解析器:
$dom = new DOMDocument;
$dom->loadHTML($html);
foreach ($dom->getElementsByTagName('img') as $image) {
$src = $image->getAttribute('src');
$extension = pathinfo($src, PATHINFO_EXTENSION);
if ($extension !== 'img') {
echo $src . PHP_EOL;
}
}