Question

请帮帮我..我不知道为什么我的PHP代码中没有输出。下面是我的index.php代码

<html>
<body>

<form action="search.php" method="POST">
<input type="text" name"number" placeholder="Search...."><br/>
<input type = "submit" value="Search">

</form>

</body>
</html>

这是我的search.php。

<html>
<body>
<?php

mysql_connect("localhost","root",""); 
mysql_select_db("login");

$initial = mysql_real_escape_string($_POST['initial']);

$find_videos = mysql_query("SELECT * FROM `sigup` WHERE `initial` LIKE '%initial%'");

while($row = mysql_fetch_assoc($find_videos))
{
$name = $row['name'];
echo "$name<br/ >";
}
?>
</body>
</html>

Answer 1

 mysql_query("SELECT * FROM `sigup` WHERE `initial` LIKE '%$initial%'");

 <input type="text" name="initial" placeholder="Search....">

Answer 2

<html>
<body>

<form action="search.php" method="POST">
<input type="text" name="initial" placeholder="Search...."><br/>
<input type = "submit" value="Search">

</form>

</body>
</html>

<强>的search.php

<html>
<body>
<?php

mysql_connect("localhost","root",""); 
mysql_select_db("login");

$initial = mysql_real_escape_string($_POST['initial']);

$find_videos = mysql_query("SELECT * FROM `sigup` WHERE `initial` LIKE '%$initial%'");

while($row = mysql_fetch_assoc($find_videos))
{
$name = $row['name'];
echo "$name<br/ >";
}
?>
</body>
</html>

Answer 3

    <html>
    <body>

    <form action="search.php" method="POST">
    <input type="text" name="number" placeholder="Search...."><br/>
     <input type = "submit" value="Search">

    </form>

  </body>
</html>

的search.php

    <html>
    <body>
    <?php
    mysql_connect("localhost","root",""); 
    mysql_select_db("login");
    $initial = mysql_real_escape_string($_POST['number']);
    $find_videos = mysql_query("SELECT * FROM sigup  WHERE initial LIKE '%initial%'");
    while($row = mysql_fetch_assoc($find_videos))
    {
    $name = $row['name'];
    echo "$name";
    }
    ?>
    </body>
   </html>

在我的PHP代码中没有输出

3 个答案: