Question

首先：我有以下字符串内容

Autumn, tree leafs<BR/><BR/><a title='Autumn, tree' href='http://site.net/share-picture/3K'><img width='225px' src='http://site.net/_s/upload/2013/11/29/0be99469a67aaf35b30b236e8ee9faa3.jpg225.jpg' title='Autumn, tree leafs' alt='Autumn, tree leafs'/></a><br/>。

现在，我想要的是剪切该字符串的一部分，特别是http://site.net/_s/upload/2013/11/29/0be99469a67aaf35b30b236e8ee9faa3.jpg225.jpg，附属于src标记。

我做的是：

function imgSrc($content){ 
    $srcPos = strpos($content, 'src');
    $srcCut = substr($content, $srcPos+5);

    return $srcCut;
}

该功能的结果是http://site.net/_s/upload/2013/11/29/0be99469a67aaf35b30b236e8ee9faa3.jpg225.jpg' title='Autumn, tree leafs and big clock' alt='Autumn, tree leafs and big clock'/>。

但我想要的只是http://site.net/_s/upload/2013/11/29/0be99469a67aaf35b30b236e8ee9faa3.jpg225.jpg。

Answer 1

试试这个

echo rtrim(strstr($str," title",true),"'");

即

function imgSrc($content){ 
    $srcPos = strpos($content, 'src');
    $srcCut = substr($content, $srcPos+5);
    $srcCut = rtrim(strstr($srcCut," title",true),"'"); //Added here

    return $srcCut;
}

Answer 2

你应该查看正则表达式。永远有效：）

$string = "Autumn, tree leafs<BR/><BR/><a title='Autumn, tree' href='http://site.net/share-picture/3K'><img width='225px' src='http://site.net/_s/upload/2013/11/29/0be99469a67aaf35b30b236e8ee9faa3.jpg225.jpg' title='Autumn, tree leafs' alt='Autumn, tree leafs'/></a><br/>";

$count = preg_match_all('/src=(["\'])(.*?)\1/', $string, $match);
if ($count === FALSE) {
    print 'Nada\n';
} else { 
    print_r($match[2]);
}

从一个位置切换到另一个位置

2 个答案: