Question

你好我试着加入两张桌子这是我的简单的SQL查询

$sql="SELECT windows_users_image_upload.*, `windows_users_info`.`display`
                FROM `windows_users_image_upload`,`windows_users_info`
                WHERE `windows_users_info`.`user_id` = `windows_users_image_upload`.`user_id`
                AND ".$field."=".$value;

它的工作正常，但我想将其设置为编码器方式
并尝试这样的事情。

$this->db->select("windows_users_image_upload.*,windows_users_info.display");
        $this->db->from("windows_users_info,windows_users_image_upload");
        $this->db->where("windows_users_image_upload.".$field,$value);
        $this->db->limit($takeTuple, $startTuple);
        $this->db->join("windows_users_image_upload,windows_users_image_upload.user_id = windows_users_info.user_id");
        $result = $this->db->get()->result();

但它显示我的错误
消息：CI_DB_active_record缺少参数2 :: join（）

我该如何解决这个问题感谢。

Answer 1

这是您在CodeIgniter中使用联接的方式：

$this->db->select('*');
$this->db->from('blogs');
$this->db->join('comments', 'comments.id = blogs.id');

$query = $this->db->get();

// Produces:
// SELECT * FROM blogs
// JOIN comments ON comments.id = blogs.id1

您可以在CodeIgniter的用户指南中看到它。

http://ellislab.com/codeigniter/user-guide/database/active_record.html#select

Answer 2

您必须从命令中删除第二个表：

示例：

 $this->db->select('windows_users_image_upload.*,windows_users_info.display');
 $this->db->from('windows_users_info');
 $this->db->join("windows_users_image_upload","windows_users_image_upload.user_id = windows_users_info.user_id");
 $this->db->where("windows_users_image_upload.".$field,$value);

 $query = $this->db->get();

想要设置codeigniter连接查询

2 个答案: