Question

我正在尝试使用asmack 18连接到gtlak服务器以进行XMPP连接。

public static final String HOST = "talk.google.com";
public static final int PORT = 5222;
public static final String SERVICE = "gmail.com";

ConnectionConfiguration connConfig = new ConnectionConfiguration(HOST, PORT, SERVICE);
    XMPPConnection connection = new XMPPConnection(connConfig);

    try {
      //Connect to the server
      connection.connect();
      connection.login("xxxxxxxx@gmail.com", "password");
    // Set the status to available
      Presence presence = new Presence(Presence.Type.available);
      connection.sendPacket(presence);
      //xmppClient.setConnection(connection);
      Log.d("connection","connection successfull");
    } catch (XMPPException ex) {
      connection = null;
      Log.d("connection","connection fail");
      //Unable to connect to server
    }

但它会给出超时错误。 talk.google.com:5222例外：无法连接到talk.google.com:5222。：remote-server-timeout（504） - 由：java.net.UnknownHostException：talk.google.com

引起

Answer 1

阅读ReadME =）http://asmack.freakempire.de/0.8.9/README

静态代码

为了在Android上正常工作，您需要注册Smack   手动提供XMPP Providers和Extensions并初始化一些静态代码   在执行任何XMPP激活之前阻塞。调用    SmackAndroid.init（上下文）（在org.jivesoftware.smack中）会这样做   对你而言。

    SmackAndroid.init(getApplicationContext());
    ConnectionConfiguration connConfig = new ConnectionConfiguration("talk.google.com", 5222, "gmail.com");
...

Asmack 18连接：google.com:5222异常：无法连接到talk.google.com remote-server-timeout

1 个答案:

静态代码