Question

我有类似以下的MySQL：

Events
+----+------+--------------------------------+
| id | name | sites_id | created             |
+----+------+--------------------------------+
| 1  | test | 1        | 2013-11-01 00:00:00 |
| 2  | test | 1        | 2013-11-02 00:00:00 |
| 3  | test | 2        | 2013-11-13 00:00:00 |
| 4  | test | 3        | 2013-11-14 00:00:00 |
| 5  | test | 4        | 2013-11-25 00:00:00 |
+----+------+----------+---------------------+

我想要选择在48小时内创建并具有相同网站ID的事件。（在这个例子中，我希望ID 1和2）。

任何帮助都会受到赞赏，因为我已经在SQL中单独绘制了如何做到这一点。

由于

Answer 1

尝试这样的事情：

SELECT DISTINCT e1.*
FROM events e1
INNER JOIN events e2 ON e1.sites_id = e2.sites_id
  AND e1.id <> e2.id
WHERE ABS(datediff(e1.created, e2.created)) <= 2;

sqlfiddle demo

这会给你结果：

ID  NAME    SITES_ID    CREATED
2   test    1           November, 02 2013 00:00:00+0000
1   test    1           November, 01 2013 00:00:00+0000

Answer 2

我没有对此进行语法检查（因此将其视为更多指南）：

SELECT DISTINCT
    t1.id
    , t1.name 
    , t1.sites_id 
    , t1.created
FROM
    Events t1
    INNER JOIN Events t2
        ON (t2.created BETWEEN DATE_ADD(t1.created, INTERVAL -2 DAY) AND DATEADD(DAY, INTERVAL 2 DAY))
        AND t1.sites_id = t2.sites_id
        AND t1.id <> t2.id

Answer 3

你去了：

SELECT * FROM table WHERE table.created > DATE_SUB(table.created, INTERVAL 48 HOUR) GROUP BY sites_id HAVING count(*) > 1;

Answer 4

你可以这样做：

Select m.id,m.created from TPS_info m, tps_info c 
where c.created between m.created AND date_add(m.created, INTERVAL 43200 MINUTE)
group by m.id,m.sites_id

SQL小提琴：http://sqlfiddle.com/#!2/bce0c/2

MySQL：选择彼此日期范围内的行

4 个答案: