如何使用Hibernate在DB中插入'

时间:2010-01-08 15:35:45

标签: java mysql hibernate

我正在使用hibernate进行所有数据库操作。

我的问题是,我想在表格中插入一个包含'的字符串,例如rea9'ea/rea9'ea。 插入它时我得到以下异常

Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ea/rea9','6a8b2622d3b8ab7de31c0e2496cef2bd',5840,'')' at line 1 at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:406) at com.mysql.jdbc.Util.getInstance(Util.java:381)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1030)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3515)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3447)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1951) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2101)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2554) at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1761)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2046)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1964)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1949)
    at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.executeUpdate(NewProxyPreparedStatement.java:105)
    at org.hibernate.engine.query.NativeSQLQueryPlan.performExecuteUpdate(NativeSQLQueryPlan.java:165)
    ... 8 more

如何解决问题?

1 个答案:

答案 0 :(得分:2)

首先,您是否已将表格映射到POJO?当然,这是使Hibernate如此强大的核心所在。如果有,那么插入任何字符串都很简单:

MyPOJO m = new MyPOJO();
m.setName("asdf'!@#$%^&*()\"1234567890");
HibernateUtil.currentSession().save(m);

如果需要在HQL语句中包含任何字符串,那么它应该是一个参数:

HibernateUtil.currentSession().createQuery("from MyTable where Name=:name")
            .setParameter("name","asdf'!@#$%^&*()\"1234567890")
            .list();