Question

我正在加入page_content表，之后两个表都有sef_url列以下代码返回错误。是否有可能在CDbCriteria->select

中使用AS'alias_name'

$criteria=new CDbCriteria;
$criteria->alias = 'p';
$criteria->select = array('p.sef_url, p.date_last_modified, pc.sef_url AS parent_sef_url');
$criteria->join = 'LEFT JOIN page_content pc ON p.parent_pageid = pc.pageid';

$criteria->condition = 'p.published=:published AND p.sitemap_index=:sitemap_index';
$criteria->params = array(':published'=>1,':sitemap_index'=>0); 

$result_arr = parent::model()->findAll($criteria);

echo '<pre>';
print_r($result_arr);

foreach($result_arr as $row) {
  echo $row['parent_sef_url'];
}

Answer 1

您还应该定义一个关系：

public function relations()
{
    return array(
        'parentPageContent'=>array(self::BELONGS_TO, 'PageItem', 'parent_pageid'),
    );
}

在你能做到之后：

$pageContents = PageContent::model()->with('parentPageContent')->findAllByAttributes(array(':published'=>1,':sitemap_index'=>0));
foreach($pageContents as $pageContent){
    echo $pageContent->parentPageContent->sef_url;
}

Yii CDbCriteria选择AS别名

1 个答案: