Question

我正在尝试对一些运行测试文件的测试进行元编程。我想为每个文件创建一个测试类。每个类都应该将文件名作为类变量或等效文件，以便它在正确的文件上执行测试。但是，我无法找到一种方法来为每个类别区分这些变量。在我当前的代码中，所有都将具有相同的类变量。我怎样才能做到这一点？

module SomeFileTest
  # create a test class for every profile
  Dir.glob(File.dirname(__FILE__) + '/*.json') do |file|
    # test class
    test_class = Class.new(MiniTest::Unit::TestCase) do
       # this var should be the #{file} var for each iteration
      @@filename = file
      @json

      def setup
        begin
          @json = JSON.parse(File.read(@@filename))
        rescue JSON::ParserError
          assert(@json != nil, "JSON structure is not wellformed")
        end
      end

      # test some things in te file
      define_method("test_duplicates") do
        # ...
      end

    end

    # self-descriptive classname
    filename = File.basename(file, ".json")
    classname = "Test#{filename.capitalize}"
    self.const_set(classname, test_class)

  end
end

Answer 1

我认为问题是@@filename是一个类变量。在继承时，类变量在ruby中表现得有点直觉，这就是我通常避免它们的原因。试试这个：

module SomeFileTest
  # create a test class for every profile
  Dir.glob(File.dirname(__FILE__) + '/*.json') do |file|
    # test class
    test_class = Class.new(MiniTest::Unit::TestCase) do
       # this var should be the #{file} var for each iteration
      @filename = file
      def self.filename
        @filename
      end
      @json

      def setup
        begin
          @json = JSON.parse(File.read(self.class.filename))
        rescue JSON::ParserError
          assert(@json != nil, "JSON structure is not wellformed")
        end
      end

      # test some things in te file
      define_method("test_duplicates") do
        # ...
      end

    end

    # self-descriptive classname
    filename = File.basename(file, ".json")
    classname = "Test#{filename.capitalize}"
    self.const_set(classname, test_class)

  end
end

将一个独特的类变量注入元编程类

1 个答案: